Re: AW: signout and redirect
so what is the solution for my case ?
James Carman-3 wrote:
>
> By default, Wicket uses the KeyInSessionSunJceCryptFactory which
> stores the encryption key in the user's session.
>
> On Thu, Mar 25, 2010 at 11:50 AM, fachhoch wrote:
>>
>> does encryption has anything to do with this upon debugging I found its
>> failing in CryptedUrlWebRequestCodingStrategy.java
>>
>> here is the method where it fails
>>
>> protected String decodeURL(final String url)
>> {
>> int startIndex = url.indexOf("?x=");
>> if (startIndex == -1)
>> {
>> startIndex = url.indexOf("&x=");
>> }
>>
>> if (startIndex != -1)
>> {
>> try
>> {
>> startIndex = startIndex + 3;
>> final int endIndex = url.indexOf("&",
>> startIndex);
>> String secureParam;
>> if (endIndex == -1)
>> {
>> secureParam =
>> url.substring(startIndex);
>> }
>> else
>> {
>> secureParam =
>> url.substring(startIndex, endIndex);
>> }
>>
>> secureParam =
>> WicketURLDecoder.QUERY_INSTANCE.decode(secureParam);
>>
>> // Get the crypt implementation from the
>> application
>> final ICrypt urlCrypt = Application.get()
>> .getSecuritySettings()
>> .getCryptFactory()
>> .newCrypt();
>>
>> // Decrypt the query string
>> String queryString =
>> urlCrypt.decryptUrlSafe(secureParam);
>>
>> // The querystring might have been
>> shortened (length reduced).
>> // In that case, lengthen the query string
>> again.
>> queryString = rebuildUrl(queryString);
>> return queryString;
>> }
>> catch (Exception ex)
>> {
>> return onError(ex, url);
>> }
>> }
>> return null;
>> }
>> it fails at this line
>> String queryString = urlCrypt.decryptUrlSafe(secureParam);
>>
>> why decrypt fails if session is invalidated ?
>>
>> James Carman-3 wrote:
>>>
>>> This works for me:
>>>
>>> final Link signOutLink = new Link("signOutLink")
>>> {
>>> public void onClick()
>>> {
>>> getSession().invalidate();
>>> setResponsePage(getApplication().getHomePage());
>>> setRedirect(true);
>>> }
>>>
>>> public boolean isVisible()
>>> {
>>> return ((MySessionClass)getSession()).isSignedIn();
>>> }
>>> };
>>>
>>> I put that in my "base page" class so that it's visible everywhere.
>>>
>>> On Thu, Mar 25, 2010 at 11:30 AM, fachhoch wrote:
I did as u said
public class AuditSignOutPage extends SignOutPage
{
public AuditSignOutPage() {
((AuditWebSession)(Session.get())).signout();
setRedirect(true);
throw new
RestartResponseException(SSISignOutPage.class);
}
}
public class SSISignOutPage extends UnSecuredBasePage {
public SSISignOutPage() {
add(new AjaxLink("relogin"){
�...@override
public void onClick(AjaxRequestTarget target) {
setResponsePage(new
AuditWicketApplication.SignInPageHelper().getSignInPage());
setRedirect(true);
}
});
}
}
I click on the signout link AuditSignOutPage invalidates the
session
and send to SSISignOutPage .here this page gets loaded , I see the
link
relogin.
when I click on the link relogin it should take me to my signinpage
but
again i am ending up with session expired page . I set the break
point
in onClick method but it never goes there ,
please explain me what could be causing this ?
Mauro Ciancio wrote:
>
> In order to implement my sign out page I've created a SignOutPage
> that invokes the signOut method in AuthenticatedWebSession, then
> setRedirect(true) and as final step I throw a:
>
Re: AW: signout and redirect
By default, Wicket uses the KeyInSessionSunJceCryptFactory which
stores the encryption key in the user's session.
On Thu, Mar 25, 2010 at 11:50 AM, fachhoch wrote:
>
> does encryption has anything to do with this upon debugging I found its
> failing in CryptedUrlWebRequestCodingStrategy.java
>
> here is the method where it fails
>
> protected String decodeURL(final String url)
> {
> int startIndex = url.indexOf("?x=");
> if (startIndex == -1)
> {
> startIndex = url.indexOf("&x=");
> }
>
> if (startIndex != -1)
> {
> try
> {
> startIndex = startIndex + 3;
> final int endIndex = url.indexOf("&",
> startIndex);
> String secureParam;
> if (endIndex == -1)
> {
> secureParam =
> url.substring(startIndex);
> }
> else
> {
> secureParam =
> url.substring(startIndex, endIndex);
> }
>
> secureParam =
> WicketURLDecoder.QUERY_INSTANCE.decode(secureParam);
>
> // Get the crypt implementation from the
> application
> final ICrypt urlCrypt = Application.get()
> .getSecuritySettings()
> .getCryptFactory()
> .newCrypt();
>
> // Decrypt the query string
> String queryString =
> urlCrypt.decryptUrlSafe(secureParam);
>
> // The querystring might have been shortened
> (length reduced).
> // In that case, lengthen the query string
> again.
> queryString = rebuildUrl(queryString);
> return queryString;
> }
> catch (Exception ex)
> {
> return onError(ex, url);
> }
> }
> return null;
> }
> it fails at this line
> String queryString = urlCrypt.decryptUrlSafe(secureParam);
>
> why decrypt fails if session is invalidated ?
>
> James Carman-3 wrote:
>>
>> This works for me:
>>
>> final Link signOutLink = new Link("signOutLink")
>> {
>> public void onClick()
>> {
>> getSession().invalidate();
>> setResponsePage(getApplication().getHomePage());
>> setRedirect(true);
>> }
>>
>> public boolean isVisible()
>> {
>> return ((MySessionClass)getSession()).isSignedIn();
>> }
>> };
>>
>> I put that in my "base page" class so that it's visible everywhere.
>>
>> On Thu, Mar 25, 2010 at 11:30 AM, fachhoch wrote:
>>>
>>> I did as u said
>>> public class AuditSignOutPage extends SignOutPage
>>> {
>>>
>>> public AuditSignOutPage() {
>>> ((AuditWebSession)(Session.get())).signout();
>>> setRedirect(true);
>>> throw new RestartResponseException(SSISignOutPage.class);
>>> }
>>> }
>>>
>>>
>>> public class SSISignOutPage extends UnSecuredBasePage {
>>>
>>> public SSISignOutPage() {
>>> add(new AjaxLink("relogin"){
>>> �...@override
>>> public void onClick(AjaxRequestTarget target) {
>>> setResponsePage(new
>>> AuditWicketApplication.SignInPageHelper().getSignInPage());
>>> setRedirect(true);
>>> }
>>> });
>>> }
>>> }
>>> I click on the signout link AuditSignOutPage invalidates the session
>>> and send to SSISignOutPage .here this page gets loaded , I see the
>>> link
>>> relogin.
>>>
>>> when I click on the link relogin it should take me to my signinpage but
>>> again i am ending up with session expired page . I set the break point
>>> in onClick method but it never goes there ,
>>>
>>> please explain me what could be causing this ?
>>>
>>>
>>>
>>> Mauro Ciancio wrote:
In order to implement my sign out page I've created a SignOutPage
that invokes the signOut method in AuthenticatedWebSession, then
setRedirect(true) and as final step I throw a:
throw new RestartResponseException(HomePage.class).
This makes the home page be processed (and the url in the navigation
bar remains /your_home_page_url).
Here is the full code if you ne
Re: AW: signout and redirect
does encryption has anything to do with this upon debugging I found its
failing in CryptedUrlWebRequestCodingStrategy.java
here is the method where it fails
protected String decodeURL(final String url)
{
int startIndex = url.indexOf("?x=");
if (startIndex == -1)
{
startIndex = url.indexOf("&x=");
}
if (startIndex != -1)
{
try
{
startIndex = startIndex + 3;
final int endIndex = url.indexOf("&",
startIndex);
String secureParam;
if (endIndex == -1)
{
secureParam = url.substring(startIndex);
}
else
{
secureParam = url.substring(startIndex,
endIndex);
}
secureParam =
WicketURLDecoder.QUERY_INSTANCE.decode(secureParam);
// Get the crypt implementation from the
application
final ICrypt urlCrypt = Application.get()
.getSecuritySettings()
.getCryptFactory()
.newCrypt();
// Decrypt the query string
String queryString =
urlCrypt.decryptUrlSafe(secureParam);
// The querystring might have been shortened
(length reduced).
// In that case, lengthen the query string
again.
queryString = rebuildUrl(queryString);
return queryString;
}
catch (Exception ex)
{
return onError(ex, url);
}
}
return null;
}
it fails at this line
String queryString = urlCrypt.decryptUrlSafe(secureParam);
why decrypt fails if session is invalidated ?
James Carman-3 wrote:
>
> This works for me:
>
> final Link signOutLink = new Link("signOutLink")
> {
> public void onClick()
> {
> getSession().invalidate();
> setResponsePage(getApplication().getHomePage());
> setRedirect(true);
> }
>
> public boolean isVisible()
> {
> return ((MySessionClass)getSession()).isSignedIn();
> }
> };
>
> I put that in my "base page" class so that it's visible everywhere.
>
> On Thu, Mar 25, 2010 at 11:30 AM, fachhoch wrote:
>>
>> I did as u said
>> public class AuditSignOutPage extends SignOutPage
>> {
>>
>> public AuditSignOutPage() {
>> ((AuditWebSession)(Session.get())).signout();
>> setRedirect(true);
>> throw new RestartResponseException(SSISignOutPage.class);
>> }
>> }
>>
>>
>> public class SSISignOutPage extends UnSecuredBasePage {
>>
>> public SSISignOutPage() {
>> add(new AjaxLink("relogin"){
>> �...@override
>> public void onClick(AjaxRequestTarget target) {
>> setResponsePage(new
>> AuditWicketApplication.SignInPageHelper().getSignInPage());
>> setRedirect(true);
>> }
>> });
>> }
>> }
>> I click on the signout link AuditSignOutPage invalidates the session
>> and send to SSISignOutPage .here this page gets loaded , I see the
>> link
>> relogin.
>>
>> when I click on the link relogin it should take me to my signinpage but
>> again i am ending up with session expired page . I set the break point
>> in onClick method but it never goes there ,
>>
>> please explain me what could be causing this ?
>>
>>
>>
>> Mauro Ciancio wrote:
>>>
>>> In order to implement my sign out page I've created a SignOutPage
>>> that invokes the signOut method in AuthenticatedWebSession, then
>>> setRedirect(true) and as final step I throw a:
>>>
>>> throw new RestartResponseException(HomePage.class).
>>>
>>> This makes the home page be processed (and the url in the navigation
>>> bar remains /your_home_page_url).
>>>
>>> Here is the full code if you need it:
>>>
>>> public class LogOutPage extends WebPage {
>>>
>>> public LogOutPage() {
>>> AuthenticatedWebSession.get().signOut();
>>> setRedirect(true);
>>> throw new RestartResponseException(HomePage.class);
>>> }
>>> }
>>>
>>> Cheers.
>>>
>>> On Thu, Mar 25, 2010 at 11:19 AM, fa
Re: AW: signout and redirect
This works for me:
final Link signOutLink = new Link("signOutLink")
{
public void onClick()
{
getSession().invalidate();
setResponsePage(getApplication().getHomePage());
setRedirect(true);
}
public boolean isVisible()
{
return ((MySessionClass)getSession()).isSignedIn();
}
};
I put that in my "base page" class so that it's visible everywhere.
On Thu, Mar 25, 2010 at 11:30 AM, fachhoch wrote:
>
> I did as u said
> public class AuditSignOutPage extends SignOutPage
> {
>
> public AuditSignOutPage() {
> ((AuditWebSession)(Session.get())).signout();
> setRedirect(true);
> throw new RestartResponseException(SSISignOutPage.class);
> }
> }
>
>
> public class SSISignOutPage extends UnSecuredBasePage {
>
> public SSISignOutPage() {
> add(new AjaxLink("relogin"){
> �...@override
> public void onClick(AjaxRequestTarget target) {
> setResponsePage(new
> AuditWicketApplication.SignInPageHelper().getSignInPage());
> setRedirect(true);
> }
> });
> }
> }
> I click on the signout link AuditSignOutPage invalidates the session
> and send to SSISignOutPage .here this page gets loaded , I see the link
> relogin.
>
> when I click on the link relogin it should take me to my signinpage but
> again i am ending up with session expired page . I set the break point
> in onClick method but it never goes there ,
>
> please explain me what could be causing this ?
>
>
>
> Mauro Ciancio wrote:
>>
>> In order to implement my sign out page I've created a SignOutPage
>> that invokes the signOut method in AuthenticatedWebSession, then
>> setRedirect(true) and as final step I throw a:
>>
>> throw new RestartResponseException(HomePage.class).
>>
>> This makes the home page be processed (and the url in the navigation
>> bar remains /your_home_page_url).
>>
>> Here is the full code if you need it:
>>
>> public class LogOutPage extends WebPage {
>>
>> public LogOutPage() {
>> AuthenticatedWebSession.get().signOut();
>> setRedirect(true);
>> throw new RestartResponseException(HomePage.class);
>> }
>> }
>>
>> Cheers.
>>
>> On Thu, Mar 25, 2010 at 11:19 AM, fachhoch wrote:
>>>
>>> I initially tried etResponsePage(SSISignOutPage.class) it did not
>>> worked ,
>>> so used the new approach ,
>>>
>>> regarding what my SSISignOutPage it does nothing except for showing a
>>> link
>>> , before to that the control never goes to the page constructor ,
>>>
>>> I am assuming after a session is invalidated wicket removes all its
>>> pages
>>> from page map and its possible that it cannot find the page
>>> SSISignOutPage
>>> and for that reason do I get pageExpired error ?
>>>
>>>
>>>
>>>
>>> christian.giambalvo wrote:
Depends on what your SSISignOutPage.class does.
But why don't use setResponsePage(SSISignOutPage.class) ??
-Ursprüngliche Nachricht-
Von: tubin gen [mailto:fachh...@gmail.com]
Gesendet: Donnerstag, 25. März 2010 12:59
An: users
Betreff: signout and redirect
here is my code to signout link.
add(new Link("signout"){
@Override
public void onClick() {
((AuditWebSession)(Session.get())).signout();
throw new RestartResponseException(SSISignOutPage.class);
}
});
when user clicks on signout I expect to go to SSISignOutPage.
but I end up with a different page which is set in applicationsettings
IApplicationSettings settings= super.getApplicationSettings();
settings.setPageExpiredErrorPage(SessionExpiredPage.class);
the SessionExpiredPage .
please tell me what could be causing this ?
-
To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
For additional commands, e-mail: users-h...@wicket.apache.org
>>>
>>> --
>>> View this message in context:
>>> http://old.nabble.com/signout-and-redirect-tp28027857p28029507.html
>>> Sent from the Wicket - User mailing list archive at Nabble.com.
>>>
>>>
>>> -
>>> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
>>> For additional commands, e-mail: users-h...@wicket.apache.org
>>>
>>>
>>
>>
>>
>> --
>> Mauro Ciancio
>>
>> -
>> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
>> For additional commands, e-mail: users-h...@wicket.apache.org
>>
>>
>>
>
> --
> View this message in context:
> http://old.nabble.com/signout-and-redirect-tp28027857p28030542.html
> Sent from the
Re: AW: signout and redirect
I did as u said
public class AuditSignOutPage extends SignOutPage
{
public AuditSignOutPage() {
((AuditWebSession)(Session.get())).signout();
setRedirect(true);
throw new RestartResponseException(SSISignOutPage.class);
}
}
public class SSISignOutPage extends UnSecuredBasePage {
public SSISignOutPage() {
add(new AjaxLink("relogin"){
@Override
public void onClick(AjaxRequestTarget target) {
setResponsePage(new
AuditWicketApplication.SignInPageHelper().getSignInPage());
setRedirect(true);
}
});
}
}
I click on the signout link AuditSignOutPage invalidates the session
and send to SSISignOutPage .here this page gets loaded , I see the link
relogin.
when I click on the link relogin it should take me to my signinpage but
again i am ending up with session expired page . I set the break point
in onClick method but it never goes there ,
please explain me what could be causing this ?
Mauro Ciancio wrote:
>
> In order to implement my sign out page I've created a SignOutPage
> that invokes the signOut method in AuthenticatedWebSession, then
> setRedirect(true) and as final step I throw a:
>
> throw new RestartResponseException(HomePage.class).
>
> This makes the home page be processed (and the url in the navigation
> bar remains /your_home_page_url).
>
> Here is the full code if you need it:
>
> public class LogOutPage extends WebPage {
>
> public LogOutPage() {
> AuthenticatedWebSession.get().signOut();
> setRedirect(true);
> throw new RestartResponseException(HomePage.class);
> }
> }
>
> Cheers.
>
> On Thu, Mar 25, 2010 at 11:19 AM, fachhoch wrote:
>>
>> I initially tried etResponsePage(SSISignOutPage.class) it did not
>> worked ,
>> so used the new approach ,
>>
>> regarding what my SSISignOutPage it does nothing except for showing a
>> link
>> , before to that the control never goes to the page constructor ,
>>
>> I am assuming after a session is invalidated wicket removes all its
>> pages
>> from page map and its possible that it cannot find the page
>> SSISignOutPage
>> and for that reason do I get pageExpired error ?
>>
>>
>>
>>
>> christian.giambalvo wrote:
>>>
>>> Depends on what your SSISignOutPage.class does.
>>> But why don't use setResponsePage(SSISignOutPage.class) ??
>>>
>>> -Ursprüngliche Nachricht-
>>> Von: tubin gen [mailto:fachh...@gmail.com]
>>> Gesendet: Donnerstag, 25. März 2010 12:59
>>> An: users
>>> Betreff: signout and redirect
>>>
>>> here is my code to signout link.
>>>
>>> add(new Link("signout"){
>>> @Override
>>> public void onClick() {
>>> ((AuditWebSession)(Session.get())).signout();
>>> throw new RestartResponseException(SSISignOutPage.class);
>>> }
>>> });
>>>
>>> when user clicks on signout I expect to go to SSISignOutPage.
>>> but I end up with a different page which is set in applicationsettings
>>>
>>> IApplicationSettings settings= super.getApplicationSettings();
>>> settings.setPageExpiredErrorPage(SessionExpiredPage.class);
>>>
>>>
>>> the SessionExpiredPage .
>>> please tell me what could be causing this ?
>>>
>>> -
>>> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
>>> For additional commands, e-mail: users-h...@wicket.apache.org
>>>
>>>
>>>
>>
>> --
>> View this message in context:
>> http://old.nabble.com/signout-and-redirect-tp28027857p28029507.html
>> Sent from the Wicket - User mailing list archive at Nabble.com.
>>
>>
>> -
>> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
>> For additional commands, e-mail: users-h...@wicket.apache.org
>>
>>
>
>
>
> --
> Mauro Ciancio
>
> -
> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
> For additional commands, e-mail: users-h...@wicket.apache.org
>
>
>
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Re: AW: AW: signout and redirect
no it is not.
christian.giambalvo wrote:
>
> setResponsePage(SSISignOutPage.class) creates a new page that will go into
> pagemap.
> Is your Page class in a protected area?
>
> -Ursprüngliche Nachricht-
> Von: fachhoch [mailto:fachh...@gmail.com]
> Gesendet: Donnerstag, 25. März 2010 15:19
> An: users@wicket.apache.org
> Betreff: Re: AW: signout and redirect
>
>
> I initially tried etResponsePage(SSISignOutPage.class) it did not
> worked ,
> so used the new approach ,
>
> regarding what my SSISignOutPage it does nothing except for showing a
> link
> , before to that the control never goes to the page constructor ,
>
> I am assuming after a session is invalidated wicket removes all its pages
> from page map and its possible that it cannot find the page
> SSISignOutPage
> and for that reason do I get pageExpired error ?
>
>
>
>
> christian.giambalvo wrote:
>>
>> Depends on what your SSISignOutPage.class does.
>> But why don't use setResponsePage(SSISignOutPage.class) ??
>>
>> -Ursprüngliche Nachricht-
>> Von: tubin gen [mailto:fachh...@gmail.com]
>> Gesendet: Donnerstag, 25. März 2010 12:59
>> An: users
>> Betreff: signout and redirect
>>
>> here is my code to signout link.
>>
>> add(new Link("signout"){
>> @Override
>> public void onClick() {
>> ((AuditWebSession)(Session.get())).signout();
>> throw new RestartResponseException(SSISignOutPage.class);
>> }
>> });
>>
>> when user clicks on signout I expect to go to SSISignOutPage.
>> but I end up with a different page which is set in applicationsettings
>>
>> IApplicationSettings settings= super.getApplicationSettings();
>> settings.setPageExpiredErrorPage(SessionExpiredPage.class);
>>
>>
>> the SessionExpiredPage .
>> please tell me what could be causing this ?
>>
>> -
>> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
>> For additional commands, e-mail: users-h...@wicket.apache.org
>>
>>
>>
>
> --
> View this message in context:
> http://old.nabble.com/signout-and-redirect-tp28027857p28029507.html
> Sent from the Wicket - User mailing list archive at Nabble.com.
>
>
> -
> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
> For additional commands, e-mail: users-h...@wicket.apache.org
>
>
>
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Re: AW: signout and redirect
In order to implement my sign out page I've created a SignOutPage
that invokes the signOut method in AuthenticatedWebSession, then
setRedirect(true) and as final step I throw a:
throw new RestartResponseException(HomePage.class).
This makes the home page be processed (and the url in the navigation
bar remains /your_home_page_url).
Here is the full code if you need it:
public class LogOutPage extends WebPage {
public LogOutPage() {
AuthenticatedWebSession.get().signOut();
setRedirect(true);
throw new RestartResponseException(HomePage.class);
}
}
Cheers.
On Thu, Mar 25, 2010 at 11:19 AM, fachhoch wrote:
>
> I initially tried etResponsePage(SSISignOutPage.class) it did not worked ,
> so used the new approach ,
>
> regarding what my SSISignOutPage it does nothing except for showing a link
> , before to that the control never goes to the page constructor ,
>
> I am assuming after a session is invalidated wicket removes all its pages
> from page map and its possible that it cannot find the page SSISignOutPage
> and for that reason do I get pageExpired error ?
>
>
>
>
> christian.giambalvo wrote:
>>
>> Depends on what your SSISignOutPage.class does.
>> But why don't use setResponsePage(SSISignOutPage.class) ??
>>
>> -Ursprüngliche Nachricht-
>> Von: tubin gen [mailto:fachh...@gmail.com]
>> Gesendet: Donnerstag, 25. März 2010 12:59
>> An: users
>> Betreff: signout and redirect
>>
>> here is my code to signout link.
>>
>> add(new Link("signout"){
>> @Override
>> public void onClick() {
>> ((AuditWebSession)(Session.get())).signout();
>> throw new RestartResponseException(SSISignOutPage.class);
>> }
>> });
>>
>> when user clicks on signout I expect to go to SSISignOutPage.
>> but I end up with a different page which is set in applicationsettings
>>
>> IApplicationSettings settings= super.getApplicationSettings();
>> settings.setPageExpiredErrorPage(SessionExpiredPage.class);
>>
>>
>> the SessionExpiredPage .
>> please tell me what could be causing this ?
>>
>> -
>> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
>> For additional commands, e-mail: users-h...@wicket.apache.org
>>
>>
>>
>
> --
> View this message in context:
> http://old.nabble.com/signout-and-redirect-tp28027857p28029507.html
> Sent from the Wicket - User mailing list archive at Nabble.com.
>
>
> -
> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
> For additional commands, e-mail: users-h...@wicket.apache.org
>
>
--
Mauro Ciancio
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AW: AW: signout and redirect
setResponsePage(SSISignOutPage.class) creates a new page that will go into
pagemap.
Is your Page class in a protected area?
-Ursprüngliche Nachricht-
Von: fachhoch [mailto:fachh...@gmail.com]
Gesendet: Donnerstag, 25. März 2010 15:19
An: users@wicket.apache.org
Betreff: Re: AW: signout and redirect
I initially tried etResponsePage(SSISignOutPage.class) it did not worked ,
so used the new approach ,
regarding what my SSISignOutPage it does nothing except for showing a link
, before to that the control never goes to the page constructor ,
I am assuming after a session is invalidated wicket removes all its pages
from page map and its possible that it cannot find the page SSISignOutPage
and for that reason do I get pageExpired error ?
christian.giambalvo wrote:
>
> Depends on what your SSISignOutPage.class does.
> But why don't use setResponsePage(SSISignOutPage.class) ??
>
> -Ursprüngliche Nachricht-
> Von: tubin gen [mailto:fachh...@gmail.com]
> Gesendet: Donnerstag, 25. März 2010 12:59
> An: users
> Betreff: signout and redirect
>
> here is my code to signout link.
>
> add(new Link("signout"){
> @Override
> public void onClick() {
> ((AuditWebSession)(Session.get())).signout();
> throw new RestartResponseException(SSISignOutPage.class);
> }
> });
>
> when user clicks on signout I expect to go to SSISignOutPage.
> but I end up with a different page which is set in applicationsettings
>
> IApplicationSettings settings= super.getApplicationSettings();
> settings.setPageExpiredErrorPage(SessionExpiredPage.class);
>
>
> the SessionExpiredPage .
> please tell me what could be causing this ?
>
> -
> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
> For additional commands, e-mail: users-h...@wicket.apache.org
>
>
>
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Re: AW: signout and redirect
I initially tried etResponsePage(SSISignOutPage.class) it did not worked ,
so used the new approach ,
regarding what my SSISignOutPage it does nothing except for showing a link
, before to that the control never goes to the page constructor ,
I am assuming after a session is invalidated wicket removes all its pages
from page map and its possible that it cannot find the page SSISignOutPage
and for that reason do I get pageExpired error ?
christian.giambalvo wrote:
>
> Depends on what your SSISignOutPage.class does.
> But why don't use setResponsePage(SSISignOutPage.class) ??
>
> -Ursprüngliche Nachricht-
> Von: tubin gen [mailto:fachh...@gmail.com]
> Gesendet: Donnerstag, 25. März 2010 12:59
> An: users
> Betreff: signout and redirect
>
> here is my code to signout link.
>
> add(new Link("signout"){
> @Override
> public void onClick() {
> ((AuditWebSession)(Session.get())).signout();
> throw new RestartResponseException(SSISignOutPage.class);
> }
> });
>
> when user clicks on signout I expect to go to SSISignOutPage.
> but I end up with a different page which is set in applicationsettings
>
> IApplicationSettings settings= super.getApplicationSettings();
> settings.setPageExpiredErrorPage(SessionExpiredPage.class);
>
>
> the SessionExpiredPage .
> please tell me what could be causing this ?
>
> -
> To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org
> For additional commands, e-mail: users-h...@wicket.apache.org
>
>
>
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View this message in context:
http://old.nabble.com/signout-and-redirect-tp28027857p28029507.html
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AW: signout and redirect
Depends on what your SSISignOutPage.class does.
But why don't use setResponsePage(SSISignOutPage.class) ??
-Ursprüngliche Nachricht-
Von: tubin gen [mailto:fachh...@gmail.com]
Gesendet: Donnerstag, 25. März 2010 12:59
An: users
Betreff: signout and redirect
here is my code to signout link.
add(new Link("signout"){
@Override
public void onClick() {
((AuditWebSession)(Session.get())).signout();
throw new RestartResponseException(SSISignOutPage.class);
}
});
when user clicks on signout I expect to go to SSISignOutPage.
but I end up with a different page which is set in applicationsettings
IApplicationSettings settings= super.getApplicationSettings();
settings.setPageExpiredErrorPage(SessionExpiredPage.class);
the SessionExpiredPage .
please tell me what could be causing this ?
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For additional commands, e-mail: users-h...@wicket.apache.org
