In reply to Axil Axil's message of Fri, 29 Mar 2013 16:48:47 -0400:
Hi,
[snip]
There is a limit to stability, once stability reaches that limit, there is
no way to go but toward instability. As the EMF grows in strength, the
nuclear forces become increasingly unstable. Given a sufficiently
In reply to Axil Axil's message of Thu, 28 Mar 2013 15:54:02 -0400:
Hi,
[snip]
When two things are balanced, the balance can be upset in two ways: you can
change the first thing or you can change the second thing.
In either case the thing that was once balanced is now unbalanced.
It does not
There is a limit to stability, once stability reaches that limit, there is
no way to go but toward instability. As the EMF grows in strength, the
nuclear forces become increasingly unstable. Given a sufficiently intense
EMF field, sufficient instability can be achieved to overcome the fission
On Fri, Mar 29, 2013 at 4:48 PM, Axil Axil janap...@gmail.com wrote:
There is a limit to stability, once stability reaches that limit, there is
no way to go but toward instability.
Is this something like buckling?
Failure without breaking
http://www.youtube.com/watch?v=wrdO8hPJGyg
On Fri, Mar 29, 2013 at 6:23 PM, Harry Veeder hveeder...@gmail.com wrote:
On Fri, Mar 29, 2013 at 4:48 PM, Axil Axil janap...@gmail.com wrote:
There is a limit to stability, once stability reaches that limit, there
is no way to go but toward instability.
Is this something like buckling?
In reply to Axil Axil's message of Wed, 27 Mar 2013 17:27:07 -0400:
Hi,
[snip]
Since we know that proton charge can be screened and therefore variable,
the coulomb coefficient is reduced relative to the Asymmetry term as a
result of screening.
See
When two things are balanced, the balance can be upset in two ways: you can
change the first thing or you can change the second thing.
In either case the thing that was once balanced is now unbalanced.
It does not matter how you get to the unbalanced state, the result is the
same, fission.
On
In reply to Axil Axil's message of Mon, 25 Mar 2013 10:23:03 -0400:
Hi,
[snip]
As this positive charge is reduced, the attraction between protons and
neutrons are decreased.
Why?
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/project.html
Since we know that proton charge can be screened and therefore variable,
the coulomb coefficient is reduced relative to the Asymmetry term as a
result of screening.
See
http://en.wikipedia.org/wiki/Semi-empirical_mass_formula
On Wed, Mar 27, 2013 at 5:03 PM, mix...@bigpond.com wrote:
Thanks for the inspiration.
It has just occurred to me that the use of Ni64 which has an abundant
neutrons will be most susceptible to fission due to an imbalance of
nuclear forces; more specifically the coulomb force relative to the
Asymmetry force.
Now it makes sense that Rossi uses a
To: vortex-l@eskimo.com
Subject: EXTERNAL: Re: [Vo]:It is fission dear fellows; clear your minds of
confusion
The Bumpy Road.
The binding energy contained inside the nucleus is an uncertain thing; it goes
up and down at the whim of quantum mechanics; it varies with the uncertainty
principle
vs compressed
outside the cavity.
Fran
** **
** **
*From:* Axil Axil [mailto:janap...@gmail.com]
*Sent:* Monday, March 25, 2013 7:17 PM
*To:* vortex-l@eskimo.com
*Subject:* EXTERNAL: Re: [Vo]:It is fission dear fellows; clear your
minds of confusion
** **
The Bumpy Road
, March 26, 2013 1:43 PM
To: vortex-l@eskimo.com
Subject: Re: EXTERNAL: Re: [Vo]:It is fission dear fellows; clear your minds of
confusion
Dear Francis,
Your post got me thinking. We may have a chicken or the egg situation here.
The speed of light may well be modified in the nuclear active
repulsion which is more
stable than one without. Nature can be cruel.
Dave
-Original Message-
From: Axil Axil janap...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Mon, Mar 25, 2013 1:58 am
Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion
As the protons
.
Dave
-Original Message-
From: Axil Axil janap...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Mon, Mar 25, 2013 1:58 am
Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion
As the protons lose their charge, the neutrons in the nucleus become
without. Nature can be
cruel.
Dave
-Original Message-
From: Axil Axil janap...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Mon, Mar 25, 2013 1:58 am
Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion
As the protons lose their charge, the neutrons
-
From: Axil Axil janap...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Mon, Mar 25, 2013 1:58 am
Subject: Re: [Vo]:It is fission dear fellows; clear your minds of
confusion
As the protons lose their charge, the neutrons in the nucleus become
repulsive and push the nucleus apart
In reply to Axil Axil's message of Mon, 25 Mar 2013 03:27:46 -0400:
Hi,
[snip]
Bosons can. That is what a Bose-Einstein condensate is. It is one large
waveform added together from many small ones.
One large waveform doesn't necessarily imply that all the composite entities are
in the same place
You are right. They are in superposition. They are nowhere and everywhere
at the same time: delocalized.
This is why LENR gammas get thermalized. A fission reaction in a condensate
will spread its energy throughout the condensate,
On Mon, Mar 25, 2013 at 3:37 AM, mix...@bigpond.com wrote:
In
I'm sure I missed something crucial here.
How do protons in the nucleus lose their positive charge, and as such
presumably transform into neutrons?
IOW, what is the theorized mechanism(s) involved here?
Regards,
Steven Vincent Johnson
www.OrionWorks.com
www.zazzle.com/orionworks
Last public report did not says there was no He4, just that they did not
measure them with XRF separately, and they talk of light element...
The announce of Be and B elements are new, since they were all inside the
light elements
moreover they were testing only the NAE, not all the material
Protons don’t become neutrons, but their collective charge is screened.
This collective charge of all the protons in the nucleus is where the
coulomb barrier comes from.
When the coulomb barrier is suppressed, there must be a reduction of charge
in each and every proton in the nucleus.
As this
Since the screening comes from the geometry of the NAE, any elements can
fission and/or fusion. It is a nuclear free for all inside the NAE.
For example, a light element can become heavier because of subsequent
fusion with hydrogen.
The large verities of elements found in the transmutation
region. Is that
what we are considering in this discussion?
Dave
-Original Message-
From: mixent mix...@bigpond.com
To: vortex-l vortex-l@eskimo.com
Sent: Mon, Mar 25, 2013 3:37 am
Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply to Axil Axil's
wave
region. Is that what we are considering in this discussion?
Dave
-Original Message-
From: mixent mix...@bigpond.com
To: vortex-l vortex-l@eskimo.com
Sent: Mon, Mar 25, 2013 3:37 am
Subject: Re: [Vo]:It is fission dear fellows; clear your minds of confusion
In reply
In reply to Axil Axil's message of Mon, 25 Mar 2013 04:03:34 -0400:
Hi,
[snip]
You are right. They are in superposition. They are nowhere and everywhere
at the same time: delocalized.
This is why LENR gammas get thermalized. A fission reaction in a condensate
will spread its energy throughout
The Bumpy Road.
The binding energy contained inside the nucleus is an uncertain thing; it
goes up and down at the whim of quantum mechanics; it varies with the
uncertainty principle. This energy is comprised of two parts: a real energy
and a virtual energy. It is this virtual energy that can vary
In their report, DEFKALION said they did no isotope analysis, yet they said
there was no transmutation of Ni.
Also, they did not find Tritium, He3 or He4 among the light elements. They
found lithium, beryllium and boron, though.
It seems that each LENR reactor reflects a unique transmutation
On Sun, Mar 24, 2013 at 10:21 PM, Axil Axil janap...@gmail.com wrote:
The reaction should be called cold fission.
Yes, it is tempting to think there is fission going on (or perhaps
cluster decay).
He4 being a gas will escape the nuclear active zone before a fusion
process can build on it so
I have always thought that He4 is also a product of increase alpha decay
caused by a slight coulomb barrier lowering and not a product of fusion.
It is fission all the way, Pd/D and Ni/H.
It is tragic that fusion has confused so many excellent minds for so long.
Cheers: Axil
On Mon, Mar 25,
In reply to Axil Axil's message of Mon, 25 Mar 2013 01:21:53 -0400:
Hi,
[snip]
It is fission dear fellows; clear your minds of confusion so forget about
fusion and neutron formation.
...something has to provide the energy to initiate the fission.
Regards,
Robin van Spaandonk
As the protons lose their charge, the neutrons in the nucleus become
repulsive and push the nucleus apart.
You cannot have a nucleus full of neutrons, it just won’t do.
Charge screening means neutron repulsion. There is a wide range of charge
screening levels that can happen and an associated
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