This really is not making sense. How is opening an empty door different than just having 2 from the start? In both cases you have only 2 doors to choose from, one with the prize. Am I missing something?
Peter Greenwood --- In [email protected], Pedro <[EMAIL PROTECTED]> wrote: > > Ok, Peter, I'll try to be more clear > > you have 3 doors. Each one has 1/3 of possibility of containing the prize. You pick one door. Your chance of winning is 1/3, right? > And your chance of losing is 2/3, right? > > So, the host opens an empty door. > > You'll win without changing your door if you picked the correct one first (1/3 of posibility). And you'll lose without changing your door if you picked one of the incorrects first (2/3 of posibility). So, you'll win more times if you change your door. Is it clear now? > > Ok, if you want, you can write down all posibilities and see for yourself how many times you'll win if you don't change your choice (I actually made that when I first saw this problem). > > If it's not clear, please tell me and I'll think about a better explanation... > > Pedro > > pjgat09 <[EMAIL PROTECTED]> escreveu: > I am assuming we are using varient one. Unless varient 2 means that > all the time he will get an empty door, then they are both the same. > Anyways, > Why do you still have a 1/3 chance of getting the prize? You have 2 > doors left, one with a prize. The third door had nothing behind it, > and should just be ignored. Maybe a picture might help? > > Door1 Door2 Door3 > > You pick door2 > Host opens door1 > Door1 is empty > > [door1] Door2 Door3 > You now have 2 doors to pick from: Door2(your first choice) or door3 > This means your first choice has a 1/2 chance of being correct. > > Why does the first door still count in the chances? > > Peter Greenwood > > > --- In [email protected], "Stefan Pochmann" > <[EMAIL PROTECTED]> wrote: > > > > Shelley already mentioned it, but I'd like to point it out more > > clearly. I'll give you a new variant of the riddle that points out an > > important detail that can easily be misunderstood, leading to > > different results. > > > > ----- > > > > There are three doors, one hides a car. You pick a door. The host > > opens another and there's nothing. You choose between the two closed > > doors and get what's behind it. Should you stay or switch? > > > > ----- > > > > Variant 1: The host knows what's behind the doors and when he opens > > one, he deliberately picks an empty one. > > > > Variant 2: The host does *not* know what's behind the doors and when > > he randomly opens one, it just happens to be empty. > > > > ----- > > > > Variant 1 is the original riddle with 2/3 probability getting the car > > if you switch. Variant 2 is the new one I propose. What's your answer > > for it? > > > > Cheers! > > Stefan > > > > > > > > > SPONSORED LINKS > Jigsaw puzzle game Free puzzle inlay games Educational game and puzzle Word puzzle game Kid puzzle game Puzzle games > > --------------------------------- > YAHOO! GROUPS LINKS > > > Visit your group "speedsolvingrubikscube" on the web. > > To unsubscribe from this group, send an email to: > [EMAIL PROTECTED] > > Your use of Yahoo! Groups is subject to the Yahoo! Terms of Service. > > > --------------------------------- > > > > > > > --------------------------------- > Yahoo! doce lar. Faça do Yahoo! sua homepage. > > [Non-text portions of this message have been removed] > ------------------------ Yahoo! Groups Sponsor --------------------~--> Get fast access to your favorite Yahoo! Groups. Make Yahoo! your home page http://us.click.yahoo.com/dpRU5A/wUILAA/yQLSAA/MXMplB/TM --------------------------------------------------------------------~-> Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/speedsolvingrubikscube/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
