Hey,

You're not pointing on me when you say "you", do you?  I'm all with you 
(and pretty much the rest of the world) on this.  I now my statistics 
and probabilities well. University well :)

/Gustav

Tyson Mao skrev:

>It's a hilarious idea, but with the sad undertone that this discussion 
>has even gone this far.  The probability of winning the game if you 
>switch the door is 2/3.  We make several assumptions:
>
>No one is "out to get you."
>The host offers you the switch every single time.
>The host knows which door the prize is behind.
>Psychics are full of crap.
>
>Just play the game yourself.  This "law of large numbers" not applying 
>is false.  Probability doesn't mean that something will or won't 
>happen, it's how often it should happen.  If we carry out an infinite 
>number of tests, well, and I think it's called the central limit 
>theorem but I'm not certain, the probabilities should even out to about 
>2/3 and 1/3.  If you do it 1000 times, the probability will generally 
>come out to 2/3 and 1/3, but it won't be exact, and it could come out 
>weird... you could win 1000 times in a row.  At the same time, I could 
>tunnel through a brick wall.  That's probability.
>
>Play the game yourself.  Work out the probability, read the actual text 
>of the problem as stated on that website, and if we can agree on the 
>text of the problem, and the manner of which the game is played, there 
>is no doubt that probability is 2/3 and 1/3.  There is no +epsilon or 
>-epsilon because for the sake of a math problem, no one is right handed 
>or left handed.  No one has a preference, pure randomness is possible.
>
>Honestly, if you were playing the game, would you actually stay with 
>the door you chose because you believe the probability of you winning 
>is 1/2?  If so, you deserve to lose that car.  In fact, why don't we do 
>this.  I'll be the host of this game and I'll give you 100 trials.  The 
>prize behind the door in my game will be $5 USD.
>
>Then, you be the host, and you give me 100 trials.  The prize behind 
>the door in your game is $4 USD.  I'll switch the door every time, and 
>you keep your door every time.  If the probability is 1/2, I think you 
>stand to make $50 USD in this game.  Who's up for it?
>
>I'm putting up money here.  Those who are convinced of their answer 
>should step up.  I'm convinced of my answer, and I'm putting my money 
>where my mouth is.
>
>Tyson Mao
>MSC #631
>California Institute of Technology
>
>On Dec 28, 2005, at 1:00 PM, Gustav Fredell wrote:
>
>  
>
>>Thats a hilarious idea. Go Tyson! I just wish I could be there. I have 
>>a
>>certain tactic I'm sure works, unless you pull the Lindsey Lohan card
>>mentioned by Marco.
>>
>>/Gustav
>>
>>Tyson Mao skrev:
>>
>>    
>>
>>>I'm going to set up this game, but instead of a car as a prize, as I'm
>>>obviously not that wealthy, I'll give away free cubes.  We'll do this
>>>in San Francisco during the break and we'll just call up random 
>>>members
>>>of the audience who are there spectating the competition.  If I have
>>>enough cubes, I'll do it 10 times.
>>>
>>>Tyson Mao
>>>MSC #631
>>>California Institute of Technology
>>>
>>>On Dec 28, 2005, at 12:46 PM, Rune Wesström wrote:
>>>
>>>      
>>>
>>>>"Good thinking Stefan!" ? He is contradicting himself when saying:
>>>>"you can gain some knowledge this way and be more sure that changing
>>>>would be better...but... the probability stays at 2/3". But if we had
>>>>a probability of 2/3 whithout this knowledge and then bettered it, 
>>>>how
>>>>can we still stay at 2/3?  He is discussing the a priori 
>>>>probabilities
>>>>before the first choise, *I* am discussing the probabilities before
>>>>the second choice, that is, when the host has opened one door. There
>>>>is some concensus here that the probabilities are 1/3 or 2/3. But if
>>>>we accept the theoretical assumtion (Pochmann apparently does) that
>>>>the host has an "easy" door and a "difficult" door and he chooses the
>>>>first with a probability of 1/2 + epsilon and the second with a
>>>>probability 1/2 - epsilon (epsilon not 0), the result will be 
>>>>another.
>>>>Ask mister Pochmann to calculate the probabilities for you. Mister
>>>>Bayes may help him.
>>>>R
>>>>----- Original Message -----
>>>>From: "pjgat09" <[EMAIL PROTECTED]>
>>>>To: <[email protected]>
>>>>Sent: Wednesday, December 28, 2005 5:41 PM
>>>>Subject: [Speed cubing group] Re: (Off topic)3 doors...
>>>>
>>>>
>>>>Thats the best way I have heard it put for this entire dicussion. 
>>>>Good
>>>>thinking Stefan!
>>>>
>>>>Peter Greenwood
>>>>
>>>>--- In [email protected], "Stefan Pochmann"
>>>><[EMAIL PROTECTED]> wrote:
>>>>
>>>>
>>>>        
>>>>
>>>>>This doesn't make the argument wrong. Yes, you can gain some 
>>>>>knowledge
>>>>>this way and be more sure that changing would be better. But it
>>>>>doesn't make you win more often when changing. The probability for
>>>>>that stays at 2/3.
>>>>>
>>>>>I knew a similar case as yours, but here's a really extreme one: 
>>>>>After
>>>>>you pick your first door, the host opens *all* three doors and let's
>>>>>you stay or change. Even with this 100% knowledge (because you see 
>>>>>the
>>>>>car), changing is successful exactly 2/3 of the time, namely in 
>>>>>those
>>>>>cases where you were initially wrong.
>>>>>
>>>>>Cheers!
>>>>>Stefan
>>>>>
>>>>>
>>>>>--- In [email protected], Rune Wesström <rune.
>>>>>[EMAIL PROTECTED]> wrote:
>>>>>
>>>>>
>>>>>          
>>>>>
>>>>>>A lot of  intuition!
>>>>>>You guess on door #1. The host is staying in front of door #3. Door
>>>>>>
>>>>>>
>>>>>>            
>>>>>>
>>>>>#2 is 2 meters away from him, nevertheless he opens that door. What
>>>>>would you expect to find behind door #3? A goat?! (Let us exclude
>>>>>double-crossing!).
>>>>>
>>>>>
>>>>>          
>>>>>
>>>>>>----- Original Message -----
>>>>>>From: "Stefan Pochmann" <[EMAIL PROTECTED]>
>>>>>>To: <[email protected]>
>>>>>>Sent: Wednesday, December 28, 2005 3:47 PM
>>>>>>Subject: [Speed cubing group] Re: (Off topic)3 doors...
>>>>>>
>>>>>>
>>>>>>Changing wins if and only if you initially chose the wrong door, i.
>>>>>>
>>>>>>
>>>>>>            
>>>>>>
>>>>>e.
>>>>>
>>>>>
>>>>>          
>>>>>
>>>>>>two times of three.
>>>>>>
>>>>>>Can you explain why your suggestion makes this wrong?
>>>>>>
>>>>>>Cheers!
>>>>>>Stefan
>>>>>>
>>>>>>--- In [email protected], Rune Wesström <rune.
>>>>>>[EMAIL PROTECTED]> wrote:
>>>>>>
>>>>>>
>>>>>>            
>>>>>>
>>>>>>>In real life the host is Not staying totally symmetrically in
>>>>>>>
>>>>>>>
>>>>>>>              
>>>>>>>
>>>>>>relation to the doors. (He is right-handed Or left-handed. Maybe he
>>>>>>has to take a halfstep to open a certain door etc.). If he now 
>>>>>>opens
>>>>>>the "easiest" door, Not changing wins more often than one time of
>>>>>>three. If he opens the other door, changing will win more often 
>>>>>>than
>>>>>>two times of three.
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>Yahoo! Groups Links
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