--- In [email protected], Gustav Fredell 
<[EMAIL PROTECTED]> wrote:
>
> Just to argue a bit more in this thread (which is very silly) I have 
a 
> couple of questions:
> 
> Are you suggesting that I still have 1/3, 2/3 (any way) when 
choosing at 
> random or always alternating between staying/switching? If you did 
that 
> should read 1/2, 1/2.
> 
> /Gustav


If you play randomly or alternate evenly, you'll *overall* end up with 
the car 1/2 of the time.

But the *individual* probabilities for "keep" and "switch" stay the 
same: you'll win 1/3 of all games in which you say "keep", and you'll 
win 2/3 of all games in which you say "switch".

Cheers!
Stefan






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