I just confirmed these numbers. Thought I would be first but you beat me to it :) I'll bet my testicles too.
/Gustav Tyson Mao skrev: >If you have a 1/3 probability of winning each time, and out of 100 >trials you won 76, the probability of that happening is: > >(1/3)^76*(2/3)^24*(100 nCr 76) > >Where 100 nCr 76 is 100 choose 76. I think that's correct, but I might >be wrong, but of course, that number is definitely really small. Let's >compete the probability that someone can win 76 or more times. > >Sum(i=76 to 100): (1/3)^i*(2/3)^(100-i)*(100 nCr i) > >Using Mathematica, I got 3*10^(-18). > >With that type of probability, I'd risk my testicles. And Leyan's too. > >Tyson Mao >MSC #631 >California Institute of Technology > >On Dec 28, 2005, at 7:11 PM, Stefan Pochmann wrote: > > > >>P.S. Is somebody capable of computing the odds for winning those 76 >>out of 100? >> >> > > > > > >Yahoo! Groups Links > > > > > > > > >__________ NOD32 1.1342 (20051228) Information __________ > >This message was checked by NOD32 antivirus system. >http://www.nod32.com > > > > > ------------------------ Yahoo! Groups Sponsor --------------------~--> Get fast access to your favorite Yahoo! Groups. Make Yahoo! your home page http://us.click.yahoo.com/dpRU5A/wUILAA/yQLSAA/MXMplB/TM --------------------------------------------------------------------~-> Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/speedsolvingrubikscube/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
