Stop this stupid doortalking! --- In [email protected], "Bob Burton" <[EMAIL PROTECTED]> wrote: > > --- In [email protected], "d_j_salvia" > <[EMAIL PROTECTED]> wrote: > > > I'm curious, what percentage of the time will the game be won if the > > computer contestant switches it's choice 2/3s of the time? > > In theory, it should be (2/3)*(2/3) + (1/3)*(1/3) = 5/9 of the time. > > ~ Bob >
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