I once heard a good joke...not gunna repeat it...but anyways...

I like your thinking Stefan, but I was aiming for a 1 algorithm
solution to most cases in a 4LLL...the concept you described is
actually quite wonderful...i would try it...but I'm lazy :p as you
know...but if you are a beginner who wants something easy, but also
wants to learn a more advanced solution I would suggest trying what I
suggested, as what you suggested would take more moves on average...

Craig

--- In [email protected], "Stefan Pochmann"
<[EMAIL PROTECTED]> wrote:
>
> 
> That's not what I meant. I meant applying algs to the LL only. If you 
> use that alg you mentioned on LL only, it's obvious you cannot solve 
> the whole LL no matter how often you apply it. So if it works at all, 
> then you have to apply the alg to other layers than the LL.
> 
> Also, Craig was talking about a 4-look LL and I'm after a 2-step 
> (better name than 2-look I think, but we mean the same) PLL.
> 
> To be precise: find a smallest possible set of algs that change only 
> the U layer and which solve every PLL case with at most two alg 
> applications (from that set) together with any U-turns before, between 
> or after the algs. Currently the best I know is 5.
> 
> Cheers!
> Stefan
> 
> 
> --- In [email protected], Gilles van den 
> Peereboom <[EMAIL PROTECTED]> wrote:
> >
> > Have you never heard that you can solve the LL with only 1 algorithm 
> ?
> > Just use FURU'R'F' wisely and you will be able to solve it (you 
> might
> > have to do it several times, and figure out how to combine several 
> > FURU'R'F' to affect only a few pieces.
> > I can't remember the name of the french guy who found that.
> > 
> > Have fun !
> > Gilles.
> > 
> > 
> > 2006/1/9, Stefan Pochmann <[EMAIL PROTECTED]>:
> > > --- In [email protected], "Craig Bouchard"
> > > <[EMAIL PROTECTED]> wrote:
> > > >
> > > > I think if you want a
> > > > 4LLL(every time) or less with skips...then you need to learn: 3 
> for
> > > > (as you call it) the cross on top, 4 for permuting corners...7 
> for
> > > > Orienting corners and 4 for Permuting Edges...so...3+4+7+4...18
> > > > algorithms for a guaranteed 4LLL...
> > >
> > > Be careful about the word "need" :-)
> > >
> > > Besides dropping the number for PCLL from 4 down to 2, I've taken 
> this
> > > a bit further now. You can do guaranteed 2-step PLL with a set of 
> only
> > > 5 algs. I'll use Jessica's names:
> > > http://www.ws.binghamton.edu/fridrich/Mike/permute.html
> > >
> > > (J1) = Jessica's J
> > > (J2) = L<->R mirror of (J1)
> > > (R1) = Jessica's R
> > > (R2) = L<->R mirror of (R1)
> > >
> > > You get all algs except H like this:
> > >
> > > U - (J1) y2 (J2)
> > > A - (J1) y (J2)
> > > Z - (J1) y' (R2)
> > > H - ???
> > > E - (R1) y (J2)
> > > T - (J1) U' (J2)
> > > V - (J1) y (R1) U'
> > > F - (J1) y U (R1)
> > > R - (R1)
> > > J - (J1)
> > > Y - (J1) (J2) U
> > > G1- (R1) (J2) U' d'
> > > G2- (J1) (R2) U2
> > > G3- (J2) (R1) d2
> > > G4- (R2) (J1) U' d'
> > > N - (J1) y2 (J1)
> > >
> > > So those four algs plus H guarantees 2-step PLL. Is this optimal? 
> I
> > > wouldn't be surprised if it were possible with only 4 algs.
> > >
> > > Cheers!
> > > Stefan
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > > Yahoo! Groups Links
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> >
>






 
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