yes...I knew that...

Craig

--- In [email protected], "Stefan Pochmann"
<[EMAIL PROTECTED]> wrote:
>
> Ok ok, I don't think we'll get somewhere so I'll just tell you: the 
> 3-cycles are nothing else than a swap of two adjacent corners followed 
> by a U turn. So you have these two cases:
> 
> - Swap two adjacent corners.
> - Swap two diagonal corners.
> 
> Got it?
> 
> Cheers!
> Stefan
> 
> 
> --- In [email protected], "Craig Bouchard" 
> <[EMAIL PROTECTED]> wrote:
> >
> > Well, you may be being picky and say 1, cuz if you execute one alg 
> the
> >  right way multiple times then it will solve...but I mean for a 1 
> look
> > every time...
> > 
> > Craig
> > 
> > --- In [email protected], "Stefan Pochmann"
> > <[EMAIL PROTECTED]> wrote:
> > >
> > > --- In [email protected], "Craig Bouchard" 
> > > <[EMAIL PROTECTED]> wrote:
> > > >
> > > > Yes theres 3...the 2 3 Cycles and then the one that switches the 
> 2
> > > > sets of the adjacent corners...unless you are counting the 3 
> cycles
> > > > are 1 cuz one is just the inverse...
> > > 
> > > No, the two 3-cycles are the same, and I don't mean by 
> > > inversion/mirroring. Think again :-)
> > > 
> > > > P.S. - Stefan you were the 25000th post...intense
> > > 
> > > Yeah I know. The prime factorization is 2^3 * 5^5 so if you don't 
> hear 
> > > from me again you know the Illuminati got me.
> > > 
> > > Cheers!
> > > Stefan
> > >
> >
>






 
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