That's not what I meant. I meant applying algs to the LL only. If you use that alg you mentioned on LL only, it's obvious you cannot solve the whole LL no matter how often you apply it. So if it works at all, then you have to apply the alg to other layers than the LL.
Also, Craig was talking about a 4-look LL and I'm after a 2-step (better name than 2-look I think, but we mean the same) PLL. To be precise: find a smallest possible set of algs that change only the U layer and which solve every PLL case with at most two alg applications (from that set) together with any U-turns before, between or after the algs. Currently the best I know is 5. Cheers! Stefan --- In [email protected], Gilles van den Peereboom <[EMAIL PROTECTED]> wrote: > > Have you never heard that you can solve the LL with only 1 algorithm ? > Just use FURU'R'F' wisely and you will be able to solve it (you might > have to do it several times, and figure out how to combine several > FURU'R'F' to affect only a few pieces. > I can't remember the name of the french guy who found that. > > Have fun ! > Gilles. > > > 2006/1/9, Stefan Pochmann <[EMAIL PROTECTED]>: > > --- In [email protected], "Craig Bouchard" > > <[EMAIL PROTECTED]> wrote: > > > > > > I think if you want a > > > 4LLL(every time) or less with skips...then you need to learn: 3 for > > > (as you call it) the cross on top, 4 for permuting corners...7 for > > > Orienting corners and 4 for Permuting Edges...so...3+4+7+4...18 > > > algorithms for a guaranteed 4LLL... > > > > Be careful about the word "need" :-) > > > > Besides dropping the number for PCLL from 4 down to 2, I've taken this > > a bit further now. You can do guaranteed 2-step PLL with a set of only > > 5 algs. I'll use Jessica's names: > > http://www.ws.binghamton.edu/fridrich/Mike/permute.html > > > > (J1) = Jessica's J > > (J2) = L<->R mirror of (J1) > > (R1) = Jessica's R > > (R2) = L<->R mirror of (R1) > > > > You get all algs except H like this: > > > > U - (J1) y2 (J2) > > A - (J1) y (J2) > > Z - (J1) y' (R2) > > H - ??? > > E - (R1) y (J2) > > T - (J1) U' (J2) > > V - (J1) y (R1) U' > > F - (J1) y U (R1) > > R - (R1) > > J - (J1) > > Y - (J1) (J2) U > > G1- (R1) (J2) U' d' > > G2- (J1) (R2) U2 > > G3- (J2) (R1) d2 > > G4- (R2) (J1) U' d' > > N - (J1) y2 (J1) > > > > So those four algs plus H guarantees 2-step PLL. Is this optimal? I > > wouldn't be surprised if it were possible with only 4 algs. > > > > Cheers! > > Stefan > > > > > > > > > > > > > > > > Yahoo! Groups Links > > > > > > > > > > > > > > > > > Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/speedsolvingrubikscube/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
