Hmm, then I don't understand why you said it's 3 cases.

Cheers!
Stefan

--- In [email protected], "Craig Bouchard" 
<[EMAIL PROTECTED]> wrote:
>
> yes...I knew that...
> 
> Craig
> 
> --- In [email protected], "Stefan Pochmann"
> <[EMAIL PROTECTED]> wrote:
> >
> > Ok ok, I don't think we'll get somewhere so I'll just tell you: 
the 
> > 3-cycles are nothing else than a swap of two adjacent corners 
followed 
> > by a U turn. So you have these two cases:
> > 
> > - Swap two adjacent corners.
> > - Swap two diagonal corners.
> > 
> > Got it?
> > 
> > Cheers!
> > Stefan
> > 
> > 
> > --- In [email protected], "Craig Bouchard" 
> > <[EMAIL PROTECTED]> wrote:
> > >
> > > Well, you may be being picky and say 1, cuz if you execute one 
alg 
> > the
> > >  right way multiple times then it will solve...but I mean for a 
1 
> > look
> > > every time...
> > > 
> > > Craig
> > > 
> > > --- In [email protected], "Stefan Pochmann"
> > > <[EMAIL PROTECTED]> wrote:
> > > >
> > > > --- In [email protected], "Craig 
Bouchard" 
> > > > <[EMAIL PROTECTED]> wrote:
> > > > >
> > > > > Yes theres 3...the 2 3 Cycles and then the one that switches 
the 
> > 2
> > > > > sets of the adjacent corners...unless you are counting the 3 
> > cycles
> > > > > are 1 cuz one is just the inverse...
> > > > 
> > > > No, the two 3-cycles are the same, and I don't mean by 
> > > > inversion/mirroring. Think again :-)
> > > > 
> > > > > P.S. - Stefan you were the 25000th post...intense
> > > > 
> > > > Yeah I know. The prime factorization is 2^3 * 5^5 so if you 
don't 
> > hear 
> > > > from me again you know the Illuminati got me.
> > > > 
> > > > Cheers!
> > > > Stefan
> > > >
> > >
> >
>






 
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