Le 2014-04-29 10:12, Ted Unangst a écrit : >> - Run both requests in parallel. >> - When one response is received, start a short timer (e.g. 200ms or so). >> - If the second response is received before the timer expires, sort and >> return the results as usual. >> - Otherwise, kill the second request and return what you have. > > Yuck. You just added 200ms latency to every connection.
If I'm reading the code correctly, this saves time on average even if we keep IPv4 as default, and is never worse than the current situation. getaddrinfo() queries both families in sequence. So you have to wait for the AAAA request even if the A request finishes quickly. Doesn't matter which one is first, you have to to wait for both. It makes sense to me to cap that waiting when the first request yielded results, no matter which family is the default. Please let me know if my understanding is wrong. Thanks, Simon
