Hello, I have the following directory structure for an application under Tomcat 4.1. c:\Tomcat 4.1\webapps\testapp\postform.html & c:\Tomcat 4.1\webapps\testapp\Web-inf\classes\ShowParameters.class
where testapp is my application directory. How do i set the path for the "Action" attribute in postform.html? My Action is action = "/ShowParameters Thanks. Len. --------------------------------- Do you Yahoo!? Yahoo! SiteBuilder - Free, easy-to-use web site design software
