Try adding the following to your web.xml
<servlet>
<servlet-name>ShowParameters</servlet-name>
<servlet-class>ShowParameters</servlet-class>
<!-- assumes your ShowParameters.class is not in a package -->
</servlet>
<servlet-mapping>
<servlet-name>ShowParameters</servlet-name>
<url-mapping>/ShowParameters</url-mapping>
</servlet-mapping>
NOTE: The <servlet> tags must appear before your <servlet-mapping> tags
Your servlet is now mapped to the /ShowParameters URI, so your action
attribute is correct.
This is the preferred way to map your servlets.
Alternatively, if you uncomment this part of your web.xml:
<servlet-mapping>
<servlet-name>invoker</servlet-name>
<url-pattern>/servlet/*</url-pattern>
</servlet-mapping>
Then you have already mapped /servlet/* to the invoker servlet, so you can
then set your action to "/servlet/ShowParameters". However, it opens a
security hole if you use this second approach.
-----Original Message-----
From: Lenandlar Singh [mailto:[EMAIL PROTECTED]
Sent: 22 July 2003 15:17
To: Tomcat Users List
Subject: RE: Problem with Dir Structure...
<!-- The mapping for the default servlet -->
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!-- The mapping for the invoker servlet -->
<!--
<servlet-mapping>
<servlet-name>invoker</servlet-name>
<url-pattern>/servlet/*</url-pattern>
</servlet-mapping>
-->
"Bodycombe, Andrew" <[EMAIL PROTECTED]> wrote:
It depends on your servlet mapping in the web.xml file.
-----Original Message-----
From: Lenandlar Singh [mailto:[EMAIL PROTECTED]
Sent: 22 July 2003 14:57
To: [EMAIL PROTECTED]
Subject: Problem with Dir Structure...
Hello,
I have the following directory structure for an application under
Tomcat 4.1.
c:\Tomcat 4.1\webapps\testapp\postform.html &
c:\Tomcat 4.1\webapps\testapp\Web-inf\classes\ShowParameters.class
where testapp is my application directory.
How do i set the path for the "Action" attribute in postform.html?
My Action is action = "/ShowParameters
Thanks.
Len.
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