hi,
i think this should be your servlet mapping:
<servlet-mapping>
<servlet-name>ShowParameters</servlet-name>
<url-pattern>/testapp/ShowParameters</url-pattern>
</servlet-mapping>
and so far as i know you had to do in html
action='ShowParameters' method='.. and so on.
Lenandlar Singh wrote:
Hello,
I have the following directory structure for an application under
Tomcat 4.1.
c:\Tomcat 4.1\webapps\testapp\postform.html &
c:\Tomcat 4.1\webapps\testapp\Web-inf\classes\ShowParameters.class
where testapp is my application directory.
How do i set the path for the "Action" attribute in postform.html?
My Action is action = "/ShowParameters
Thanks.
Len.
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