Message: 10
Date: Wed, 23 Nov 2005 21:19:31 -0500
From: Charles Hartman <[EMAIL PROTECTED]>
Subject: Re: OT Last week's CarTalk puzzler
To: How to use Revolution <[email protected]>
Message-ID: <[EMAIL PROTECTED]>
Content-Type: text/plain; charset=US-ASCII; delsp=yes;
format=flowed
On Nov 23, 2005, at 6:07 PM, Jim Hurley wrote:
All those numbers are called perfect squares. And only they have an
odd number of factors, because one of the factors is the square
root of the number in question. For example, nine has three
factors, 1 and 9 and 3. [I confess, I can't see how this follows.
Jim]
Well, because 9 has four factors -- 1, 3, 3, and 9 -- two of which
are assigned to the same chain-puller, who however only pulls the
chain once.
Charles
Charles,
I expressed myself badly. What I meant was that I didn't see how this
one example proved the theorem. A proof needs to show how the theorem
follows for all perfect squares and only for perfect squares, i.e. it
must be both a necessary and sufficient condition.
Jim
_______________________________________________
use-revolution mailing list
[email protected]
Please visit this url to subscribe, unsubscribe and manage your subscription
preferences:
http://lists.runrev.com/mailman/listinfo/use-revolution