Message: 10
Date: Wed, 23 Nov 2005 21:19:31 -0500
From: Charles Hartman <[EMAIL PROTECTED]>
Subject: Re: OT Last week's CarTalk puzzler
To: How to use Revolution <[email protected]>
Message-ID: <[EMAIL PROTECTED]>
Content-Type: text/plain; charset=US-ASCII; delsp=yes; format=flowed


On Nov 23, 2005, at 6:07 PM, Jim Hurley wrote:


All those numbers are called perfect squares. And only they have an odd number of factors, because one of the factors is the square root of the number in question. For example, nine has three factors, 1 and 9 and 3. [I confess, I can't see how this follows. Jim]


Well, because 9 has four factors -- 1, 3, 3, and 9 -- two of which are assigned to the same chain-puller, who however only pulls the chain once.

Charles



Charles,

I expressed myself badly. What I meant was that I didn't see how this one example proved the theorem. A proof needs to show how the theorem follows for all perfect squares and only for perfect squares, i.e. it must be both a necessary and sufficient condition.

Jim
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