Found the HP manual as suggested by Will: it is now clear where the capacitor is connected. On page 1 of the manual changes (page 3 of the PDF file) there is a very clear drawing of the quasi-inductance standard. The "C" port has no guard connections and is used to test the capacitor alone.
<https://www.valuetronics.com/Manuals/Keysight-Agilent-HP-16074A.pdf> On Fri, Aug 21, 2015 at 3:51 PM, Will <[email protected]> wrote: > Nothing new. That is actually a direct copy of a HP 16074A 4-terminal > quasi inductance standard. Even the pictures of the article were > copied directly from the HP manual. > >> 2015-08-20 11.50 UTC+03.00, Dr. David Kirkby (Kirkby Microwave Ltd) >> <[email protected]>: >> >>> If this was April the first, I would be convinced that paper was an April >>> Fools Joke! >>> >>> I can't imagine how you can make high Q (low loss) inductors, by using a >>> capacitor and two resistors. It just makes no sense to me, but I will >>> read >>> the maths later. The mere fact there is resistance makes me think it must >>> be lossy, so low Q. Also the equations seems to come out with convenient >>> numbers - R in Ohms, C in pF and H in Henries. >>> >>> But if the paper is real, it is very close to what I want, although it >>> still leaves the position of finding stable capacitors. I thought >>> inductors >>> would be easier than capacitors, but maybe not. >>> >>> Dave >>> _______________________________________________ >>> volt-nuts mailing list -- [email protected] >>> To unsubscribe, go to >>> https://www.febo.com/cgi-bin/mailman/listinfo/volt-nuts >>> and follow the instructions there. >>> >> > _______________________________________________ > volt-nuts mailing list -- [email protected] > To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/volt-nuts > and follow the instructions there. _______________________________________________ volt-nuts mailing list -- [email protected] To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/volt-nuts and follow the instructions there.
