Bob Cook <frobertc...@hotmail.com> wrote: Mixuno would see a temperature differential as you say, however what > fraction of energy introduced by the reaction is above the input energy of > the electrical pump and or other electrical inputs? >
You do not need to know this as long as you are sure the pump input is stable. With the method Mizuno uses, he measures the difference between the reactor starting baseline temperature which includes the pump input and the ending temperature. > If the reaction energy is introduced totally as heat, the determination > should be pretty good assuming the calibration of the pumps input energy is > well known. > What else could it be but heat? The calibration of the pump input is well-known because it was run for 18 hours with nothing else running. > That calibration is the question that is being debated I believe. In > Mizuno's test I believe the differential pressure that the pump put out > did not change much; hence, the energy used should follow the specification > for the pump in the pump head curve accurately. > We know it did not change much because there was no measurable variation during the time the pump was running. If the pump did more work during some hours than other hours, the temperature would vary. It does not. Really, that is all you need to know. > However, if the reaction caused a significant change in the differential > pressure and, hence, the flow . . . > The reaction produces heat only, raising the temperature of the circulating water at most 5°C. This cannot possibly affect the pump performance. > . . . such information would be necessary to accurately extrapolate the > total energy, pump plus reaction to temperatures above that produced by the > pump alone. > You do not need to extrapolate the total energy. It is irrelevant. This method does not measure total energy; it measures only additional energy on top of the baseline. - Jed
