In reply to Axil Axil's message of Thu, 12 Feb 2015 22:26:06 -0500: Hi, There isn't much to lay out. At a few hundred degrees LiAlH4 decomposes into LiH + Al + H2. At about 1000 deg. the LiH also decomposes into Li atoms and H atoms. As the LiH molecule breaks apart, there is a short period before the individual atoms separate too far, that they are within resonance range, and Hydrinos can form.
The reaction is Li + H => Li++ + H[n=1/4] + 2e- + 122.5 eV followed eventually by Li++ + 2e- (from environment) => Li + 82 eV The heat produced by these reactions helps dissociate even more LiH, resulting in more Hydrino production. IOW a positive feedback loop resulting in possible explosion if the heat is contained in a small region. If the heat has a chance to spread out, then you just get heating beyond chemistry. (BTW these reactions may also happen to some extent when a Li battery is recharged.) The newly formed Hydrinos can also pick up electrons from the environment, becoming Hydrinohydride (negatively charged ion). There is just the right ratio of H to Li in LiAlH4 for tetrahedral LiHy4- to form, which can facilitate neutron transfer reactions between Li and other nuclei. There are two reasons why it can do this. 1) LiHy4- is about 10 times smaller than a normal Hydrogen atom. This brings the nuclei much closer together (LiHy4- is negatively charged overall, so it can approach another nucleus.) 2) One of the Hy- ions at a corner of the tetrahedron will position itself between the Li nucleus and the "target" nucleus, because the Hy- is negatively charged. Now that it's in a nice straight line between the nuclei, it can act as a "stepping stone" for the neutron. IOW you get D being formed for a brief moment before the neutron moves on to the other nucleus (thanks Gullström, and also someone on this list who suggested some months back that D might form - a notion I rejected at the time because of the weakness of the p-n bond in D.) Both 1 & 2 combined, significantly enhance the likelihood of neutron tunneling. Because the neutron goes from being bound in one nucleus directly to being bound in another nucleus, there are never any free neutrons, which explains the very low neutron count associated with CF experiments. (For LiHy4- formation energies see the table at the bottom of http://rvanspaa.freehostia.com/LiHy4-.pdf) >Well lay it all out for us. Do that and I will believe. [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
