It is my understanding that even quark spin can be aligned in a strong magnetic field, since a magnetic field can penetrate right through a nucleus. It does not stop at the boundary by some magnetic stop sign. Thus I would say even your isospin particles can be polarized in a strong magnetic field in that their constituent quarks would be polarized. Somebody who has a better knowledge of quark spin may be able to correct this understanding.
Bob Bob ----- Original Message ----- From: Axil Axil To: vortex-l Sent: Tuesday, April 07, 2015 10:47 PM Subject: Re: [Vo]:mainstream physics paper bout the Hot Cat, co-author Andrea Rossi isospin is a product of the strong force and of the quarks inside the protons and neutrons. It is fixed no matter how the atoms spins. An atom might be induced to spin using EMF but usually that spin cannot effect the isospin of the nucleus. with zero isospin. Only non zero isospins are effected by RF. On Wed, Apr 8, 2015 at 1:37 AM, Bob Cook <[email protected]> wrote: Two particles spinning anti-parallel equal 0 spin if they each have an equal spin energy. Angular momentum is a vector quantity, not a scalar one. Bob ----- Original Message ----- From: Axil Axil To: vortex-l Sent: Tuesday, April 07, 2015 10:16 PM Subject: Re: [Vo]:mainstream physics paper bout the Hot Cat, co-author Andrea Rossi I don't get it. 8Be has zero nuclear spin and 4He has zero nuclear spin. How can a nuclear reaction involving them have huge annular momentum? On Wed, Apr 8, 2015 at 12:28 AM, Eric Walker <[email protected]> wrote: Hi Bob, The possibility you've been drawing attention to, that the result of the decay of the [8Be]* compound nucleus into two 4He nuclei with little linear momentum and a great deal of angular momentum makes for an interesting thought experiment. Out of curiosity, I calculated the energy that would be needed to break up an alpha particle into either tritium and a proton or 3He and a neutron, which would be the reverse of these two reactions: 3He + n → 4He + Q (19.3 MeV) t + p → 4He + Q (20.5 MeV) As I understand it, this implies that angular momentum sufficient to produce ~ 19 MeV of centripetal force would be needed to break apart a 4He into either 3He and a neutron or tritium and a proton. This suggests that a 4He can carry a large amount of angular momentum before it is likely to break apart. (I assume the process is probabilistic and that the force needed lies along a distribution.) Further comments inline. Eric On Tue, Apr 7, 2015 at 1:35 PM, Bob Cook <[email protected]> wrote: However, I know of know reason why the light nuclei cannot have any spin quantum number--high or low. Any spin quantum is available. Further to the thought experiment, I think we should make a clear distinction between two types of "spin" -- there's the actual spinning motion of a nucleus (e.g., 4He), and there is the spin state of the nucleus. At higher rates of rotation, a heavy nucleus such as an isotope of nickel will reconfigure into a higher spin state, presumably through deformation. In such a state a photon may be emitted, with the nucleus relaxing into a lower spin state. Here my mental model is of neodymium magnets spinning around in a clump. When they snap together into a lower-energy configuration, a photon is emitted through the movement of the magnets as they snap together. The photon is emitted in a direction and carries away energy in such a way as to slow the angular movement of the spinning nucleus a little (by the amount of energy carried away by the photon). The participants involved in such a transition are the nucleons, and the energy of the photon that is emitted will correspondingly be in the keV or MeV range, which is in the nuclear range. A light nucleus, such as 4He, does not have a bound excited state. My understanding is that it cannot deform under high angular momentum into a higher energy state which will emit a photon when it relaxes. The 4He will either break apart into lighter constituents under centrifugal forces or it will not. But I'm guessing that the actual moment-to-moment velocity of the 4He about its axis of motion is in principle a continuous quantity. If this is true, perhaps the energy could be released to the environment in small amounts. Where the thought experiment gets interesting is in the supposition that you and others have already offered in this thread, that charged body such as a 4He nucleus that is spinning at an incredible rate will set up a magnetic field. This magnetic field could disturb nearby electrons, causing them to emit lower energy photons in the process. Although I do not see anything special in the 7Li+p to 8Be transition that has been proposed (and note Jones's point about the gamma that would be omitted in the process), I think the more general notion of the energy of a nuclear transition somehow being deposited in angular momentum and then released in small amounts is a very interesting one.
