Robin--
Another issue to consider is the effect of the over-lying magnetic field on
the differential energy of the respective spin states and their angular
momentum. A magnetic field will separate the energies of the respective
spin states of the He* IMO. Any photon of energy would have to have a
resonance matching the original spin state and also match the energy of the
transition from spin state to spin state. It seems easier to distribute
integral quanta of angular momentum via distribution in small quanta to many
receptors.
Furthermore I am not sure that spin energy can change into photons with
their linear momentum. This assumes a transfer of linear momentum from
angular momentum. Potentially two back-to-back photons could be generated
with 0 net linear momentum. Such a transition may require two coherent He*
in anti-parallel configuration to achieve conservation of angular momentum
for the transition involving the photon emissions.
As you have noted the idea of a gamma is not consistent with the
experimental evidence, in any case.
Bob Cook
----- Original Message -----
From: <[email protected]>
To: <[email protected]>
Sent: Thursday, April 09, 2015 1:45 AM
Subject: Re: [Vo]:mainstream physics paper bout the Hot Cat, co-author
Andrea Rossi
In reply to Bob Cook's message of Tue, 7 Apr 2015 22:57:00 -0700:
Hi,
Eric--
One additional idea.
What we have been considering is the formation of 8Be and its decay into
two alpha particles with only spin energy involved.
As I have suggested before, two anti-parallel spin He* particles may form
in adjacent fcc Pd lattice locations that are stuffed tight with 2
deuterium nuclei. The net spin of the two new He* particles is high--24
mev--but amounts to 0 net angular momentum when considered as one item.
However, each He* within the coherent system may be able to distribute its
spin energy to the electrons in the vicinity, much as may happen with the
decay of the 8Be nucleus. The two LENR processes would be similar in this
regard.
Bob
[snip]
The p+Li7 reaction yields 17.35 MeV, not 24 MeV.
Based on this, and an assumption that the radius of a Helium nucleus is
about 2
fm, I calculated the angular momentum and found it to be about 2.5 times
that of
a photon, so in theory, a couple of photons could be emitted before the
nucleus
lost too much angular momentum. As to the energy of those photons that would
depend on the frequency, and that is where the ground gets a bit squishy. If
you
base it on the rotational frequency of the nucleus, then the first photon
has an
energy of about 6 MeV. This is a powerful gamma and would be easily
detected.
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/project.html
