Bob,

 

Axil is correct in that the Be-8 and He-4 cannot project large spin energy 
transfer. It does not help that spin can be anti-parallel when it is based on 0 
spin particles to begin with (they would not decay if that was the case) … 
however…

 

There is an interesting isotope of helium, generally neglected- which is indeed 
a high-spin halo nucleus – He-6. The isotope has been overlooked in LENR - but 
is so important in physics that a book has been written about it.

 

“A Cluster Model of Helium-6 and Lithium-6” by Jeremy Robert Armstrong - 
Michigan State University, Department of Physics and Astronomy, 2007 - 372 
pages. Obviously the focus is cosmology, but the fact that this high spin 
isotope is known physics is important.

 

Helium-6 is short-lived with a sub-second lifetime, but it is a borromean 
system, and thus is remarkably stable for such a high spin nucleus, and could 
convert back to lithium-6 after it has transferred MeV of spin energy to 
magnons without the timing problems faced by Hagelstein’s magic phonons.

 

http://books.google.com/books/about/A_Cluster_Model_of_Helium_6_and_Lithium.html?id=8MBxqPpWAF8C

 

I think this idea of spin energy transfer from Lithium-6 <-> Helium-6 in a 
reversible reaction powered by the strong force – and possibly even completely 
divorced from the nuclear fusion reaction, could actually be salvaged -- by the 
basic idea that lithium converts to high spin helium, and then back. Lithium-6 
is a singularity in many ways. 

 

BUT, correspondingly, the helium at the start is not Li-7, as Cook and Rossi 
claim – it is Li-6. In fact the Rossi premise is looking so bad that it is 
completely unsalvageable. The Lugano isotope data, even if it could be 
believed, completely negates the entire scenario since Li-7 is NOT depleted 
according to the Lugano report - but instead is converted to Li-6. 

 

However, a novel QCD reaction where Li-6 <-> He-6 oscillate in a reversible 
reaction, powered by the strong force, is worth pursuing – as it can provide 
spin energy to magnons at the expense of gluon mass. 

 

It’s too bad that Armstrong’s book on the above topic is not available as an 
ebook. It could be important to the idea that spin energy without high energy 
radiation, is the key to understanding this type of reaction.

 

From: Bob Cook 

 

Two particles spinning anti-parallel equal 0 spin if they each have an equal 
spin energy.  Angular momentum is a vector quantity, not a scalar one.  

 

From: Axil Axil <mailto:[email protected]>  

 

I don't get it. 8Be has zero nuclear spin and 4He has zero nuclear spin. How 
can a nuclear reaction involving them have  huge annular momentum?

 

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