In reply to Jones Beene's message of Mon, 13 Apr 2015 20:05:22 -0700: Hi, [snip] >Well, once again I will dissent, since we have had this discussion before. >It is your understanding of the fractionalization mechanism that is not >logical. What you are describing is simple ionization of the catalyst,
Correct. >and >this must precede, not cause, orbital reduction. No, it happens at the same time. That's why it's energy resonance. Energy is transferred from the H atom to the catalyst atom. The H atom gives up energy by shrinking (reduction potential energy), and the catalyst receiving the energy uses it to become ionized. Similar to the way an atom absorbing a photon may become ionized. >There is no energy to dump >until after the redundancy has completed, Where do you think it goes to in the mean time? ;) You could think of it as transfer of a virtual photon from H to catalyst. Virtual because the H can't emit a real photon, however if it's within range it can transfer the energy through the near field. You could also think of it as a resonant electrical transformer, where the H is the primary, and the catalyst is the secondary. >and Mills has clearly stated that >the neutral atom is the hydrogen - not the catalyst. It's not an either or situation. Yes, the H is neutral, but the catalyst can be anything, a neutral atom, an ion, or even a molecule. The only criterion is that it be able to resonantly absorb a multiple of 27.2 eV. A neutral Lithium atom can do this, so can e.g. a neutral K atom (81.68 eV) or an Ar+ ion (27.2 eV), or a He+ ion (54.4 eV), so can some entire molecules, which break up in the process e.g. H2O, HCl. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
