One important remark is that the interpretation of the IR camera signal might be completely wrong. The 'amplitude/time' graph shows that the threshold for white color in the XY color graph is exactly at the noise level. The noise level itself shows very low variations. If nuclear reactions / transmutations really would have occurred there would be very high peaks on top of the noise level, representing very local heat spikes. Such high peaks do not show up here. To really see nuclear spots the color graph would show white spots in a yellow, green or blue field, not in a dark red field. So in my opinion the color graph is misinterpreted.
On Tue, Apr 14, 2015 at 8:34 AM, <[email protected]> wrote: > In reply to Jones Beene's message of Mon, 13 Apr 2015 20:05:22 -0700: > Hi, > [snip] > >Well, once again I will dissent, since we have had this discussion before. > >It is your understanding of the fractionalization mechanism that is not > >logical. What you are describing is simple ionization of the catalyst, > > Correct. > > >and > >this must precede, not cause, orbital reduction. > > No, it happens at the same time. That's why it's energy resonance. Energy > is > transferred from the H atom to the catalyst atom. The H atom gives up > energy by > shrinking (reduction potential energy), and the catalyst receiving the > energy > uses it to become ionized. Similar to the way an atom absorbing a photon > may > become ionized. > > > >There is no energy to dump > >until after the redundancy has completed, > > Where do you think it goes to in the mean time? ;) > > You could think of it as transfer of a virtual photon from H to catalyst. > Virtual because the H can't emit a real photon, however if it's within > range it > can transfer the energy through the near field. You could also think of it > as a > resonant electrical transformer, where the H is the primary, and the > catalyst is > the secondary. > > >and Mills has clearly stated that > >the neutral atom is the hydrogen - not the catalyst. > > It's not an either or situation. Yes, the H is neutral, but the catalyst > can be > anything, a neutral atom, an ion, or even a molecule. The only criterion > is that > it be able to resonantly absorb a multiple of 27.2 eV. A neutral Lithium > atom > can do this, so can e.g. a neutral K atom (81.68 eV) or an Ar+ ion (27.2 > eV), or > a He+ ion (54.4 eV), so can some entire molecules, which break up in the > process > e.g. H2O, HCl. > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
