Axil, does the hydrogen have to desorb from the surface of the Ni? I liked everything you were saying to that point but still think the surface and lattice are needed to form inverse Rydberg hydrogen. I agree lack of oxygen or any reactive gases is key so the path of least resistance, covalent bond, is removed and that hydrogen could desorb from carbon at elevated temperature but think this added pressure pushes the hydrogen down into the Ni surface and NAE to form fractional hydrogen [IRH] - energy states lower than ground state afforded by vacuum suppression based on Casimir geometry. Fran
From: Axil Axil [mailto:[email protected]] Sent: Monday, October 19, 2015 4:52 PM To: vortex-l Subject: EXTERNAL: Re: [Vo]:Ni+LAH systems not performing According to Holmlid, Hydrogen Rydberg matter is formed when there is no reactive elements available to form covalent bonds. Hydrogen must interact with itself. The hydrogen must desorb from a material that does not combine with hydrogen. Carbon at elevated temperatures does not interact with hydrogen. When Rossi preprocesses his fuel, he sets up a condition were lithium and hydrogen desorb from the surface of his nickel particles at high temperatures. The same is true for Holmlid, who uses iridium as a substrate to store Hydrogen Rydberg matter produced by the iron catalyst until Holmlid hits the iridium with a laser shot. On Mon, Oct 19, 2015 at 3:38 PM, Eric Walker <[email protected]<mailto:[email protected]>> wrote: On Mon, Oct 19, 2015 at 1:39 PM, Axil Axil <[email protected]<mailto:[email protected]>> wrote: It is well known that the hydrides of group 14 elements produce Rydberg matter because of their covalent bond structure(4 bonds). These element includes include silicon and carbon. Another interesting tidbit -- both silicon and carbon have trace amounts of beta emitters: e- + 32Si => 2*e- + 2*neutrino + 32S + 1938 keV e- + 32Si => e- + neutrino + 32P + 227 keV e- + 14C => e- + neutrino + 14N + 156 keV A covalent bond could change the amount of time that the orbital electrons spend in the nuclear volume, potentially altering the beta decay rate. Because there are only trace amounts of these isotopes, I am pessimistic much heat could be derived from them. Eric
