Axil, Sounds very similar to creating the pyrophoric catalyst Rayney nickel 
where the lower melting Al is leached out of the NiAl alloy leaving nano sized 
pits. I think Mills likewise avoids reactive gases when using Rayney Ni such 
that poisoning is avoided,  H2 covalent bonding is available but reverses with 
heat and the more desirable Rydberg effect becomes available to modify the H1 
before re- associating into Rydberg molecules of varying fractional values…. 
IMHO :_)
Fran
From: Axil Axil [mailto:[email protected]]
Sent: Tuesday, October 20, 2015 12:10 PM
To: vortex-l
Subject: EXTERNAL: Re: [Vo]:Ni+LAH systems not performing

The fuel preperation process that Rossi uses as exposed in apendex 3 of the 
Lugano report shows that the surface of the 100 micron fuel particle is 
impregnated with carbon being most likely in the form of nanosized graphite 
particles. THese carbon particles are most likely melted into the surface of 
the nickel at high temperatures because the 100 micron particle gets hot enough 
to sinter many 5 micron particles together as a large aggragate.

Then pure lithium is added to cover the entire surface of the 100 micron 
particle. This converts the graphite to nanosized particles of lithium carbide. 
The LENR reaction does not occur in this preprocessing step because the 
sintering is done without hydrogen present. Rossi must uses a noble gas like 
argon or even better helium to sinter the 100 micron particle.

When the reactor is started with hydrogen, the lithium carbide gradually 
evaperates and a goodly amount of rydberg matter is produced. After a time all 
the lithium carbide is removed from the surface of the nickel particle leaving 
nano sized cavities on the surface of the nickel particles.

The surface of the ash from Lugano show no carbon remaining in the ash sample 
of the 100 micron nickel particle.

These nano cavities play a role in the continuing production of hydrogen 
rydberg matter as time goes on in the Rossi reaction.



On Tue, Oct 20, 2015 at 9:44 AM, Roarty, Francis X 
<[email protected]<mailto:[email protected]>> wrote:
Axil, does the hydrogen have to desorb from the surface of the Ni? I liked 
everything you were saying to that point but still think the surface and 
lattice are needed to form inverse Rydberg hydrogen. I agree lack of oxygen or 
any reactive gases is key so the path of least resistance, covalent bond, is 
removed and that hydrogen could desorb from carbon at elevated temperature but 
think this added pressure pushes the hydrogen down into the Ni surface and NAE 
to form fractional hydrogen [IRH] - energy states lower than ground state 
afforded by vacuum suppression based on Casimir geometry.
Fran

From: Axil Axil [mailto:[email protected]<mailto:[email protected]>]
Sent: Monday, October 19, 2015 4:52 PM
To: vortex-l
Subject: EXTERNAL: Re: [Vo]:Ni+LAH systems not performing

According to Holmlid, Hydrogen Rydberg matter is formed when there is no 
reactive elements available to form covalent bonds. Hydrogen must interact with 
itself. The hydrogen must desorb from a material that does not combine with 
hydrogen. Carbon at elevated temperatures does not interact with hydrogen.

When Rossi preprocesses his fuel, he sets up a condition were lithium and 
hydrogen desorb from the surface of his nickel particles at high temperatures. 
The same is true for Holmlid, who uses iridium as a substrate to store Hydrogen 
Rydberg matter produced by the iron catalyst until Holmlid hits the iridium 
with a laser shot.

On Mon, Oct 19, 2015 at 3:38 PM, Eric Walker 
<[email protected]<mailto:[email protected]>> wrote:
On Mon, Oct 19, 2015 at 1:39 PM, Axil Axil 
<[email protected]<mailto:[email protected]>> wrote:

It is well known that the hydrides of group 14 elements produce Rydberg matter 
because of their covalent bond structure(4 bonds). These element includes 
include silicon and carbon.

Another interesting tidbit -- both silicon and carbon have trace amounts of 
beta emitters:

e- + 32Si => 2*e- + 2*neutrino + 32S + 1938 keV
e- + 32Si => e- + neutrino + 32P + 227 keV
e- + 14C => e- + neutrino + 14N + 156 keV

A covalent bond could change the amount of time that the orbital electrons 
spend in the nuclear volume, potentially altering the beta decay rate.  Because 
there are only trace amounts of these isotopes, I am pessimistic much heat 
could be derived from them.
Eric


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