IOW, neglect the high velocity stuff (easy to do electronically)
and look for detection after at least 0.3 seconds delay.
I don't get it, what's wrong with the volunteers as you call them, aren't
they submitted to gravity too? They can be made as slow as desired using a
decelerating electrode (another grid, which would have to be grounded, so
the photocathode right below this new grid would have to be at a positive
voltage wrt ground)
What about having two of these tubes end to end but looking opposite ways,
and measuring the difference in the flight times of the fastest electrons?
One could do this once with tube 1 on top, and once with tube 2 on top, to
ascertain the effect is gravitational.
Michel
----- Original Message -----
From: "Frederick Sparber" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Friday, April 14, 2006 4:12 PM
Subject: Re: Electrogravity & Proton Repulsion of Electrons
Michel Jullian wrote.
From: "Frederick Sparber" <[EMAIL PROTECTED]>
Sent: Friday, April 14, 2006 1:27 PM
> The S1 (Cs-CsO- on Ag) Photoemissive surface is the one with the
> photon peaks at ~ 330 and ~ 800 nanometers with a threshold of about
1254
> nm (1.0 eV IR)
> Cr YAG Laser?
>
> http://ssd-rd.web.cern.ch/ssd-rd/Pad_HPD/Principle/photocathodes.htm
>
> 0.1 eV electrons have a velocity v = (0.1* 2*1.6e-19/9.1e-31)^1/2 =
> 1.875e5 meters/sec!
Checked/agreed. That's 10.66 µs for a 2m flight, quite a comfortable
thing
to measure.
But you don't want these"volunteers". :-)
> Electron space charge will act as a "velocity filter" that allows the
> higher energy electrons
> out,
Agreed, thats' a good thing since we are only interested in the fastest
electrons: they are the only one whose initial velocity we know for sure.
It lets the "volunteers" that you don't want to measure, wrt Repulsed
Electrons.
> but if there is a repulsive gravity force F(gr) = m*g = = 9.1e-31*9.8
> = 8.9e-30 newtons on an electron
> and the restraining electric field (E volts/meter)
> force F(e) = E*q = 1.6e-19 newtons at E = 1.0 volt/meter, there is a
> problem. :-)
What, which restraining electric field, where ???
Space Charge builds up due to the Image Charge around an electron
emitter, thus creating a restraining electric field. In Thermionic
Converters
it's neutralized with cesium or potassium ions.
> Sounds like a Faraday cup approach, Michel.
A Faraday saucer actually (not a joke this time, the positive collecting
plate wouldn't be hollow)
Agreed. A one or two meter evacuated (vertical height) tube with
some cesium at the bottom surface and a pulsed LED light source
at the top near the Faraday Saucer collection electrode etc..
>> Time of flight would be time between laser flash and power supply
current
>> pulse wouldn't it?
>>
> Yes. But the ~ 5 microseconds/meter 0.1 eV electrons get there ahead
> of
> the S = 0.5 * a* t^2 ~ = 3.0e-10 meters gravity repelled electrons
> traveled.
Please explain.
Use the GSU "Free Fall" calculator, except down might be up.
> OTOH. if you light pulse it and wait for the "slowpokes" ?
No, as I said we wouldn't know their initial velocity.
It doesn't really matter, as these GSU calculators show for Free Fall
(the same as an upward Repulsive Force) vs Vertical Trajectory for
those electrons that get past Image Charge and Space Charge, say
you reject any times less than 0.45 seconds the negative distance
will be minus 0.94725 meters with a "launch speed" of 0.1 meters/sec.
http://hyperphysics.phy-astr.gsu.edu/Hbase/traj.html#tra3
IOW, neglect the high velocity stuff (easy to do electronically)
and look for detection after at least 0.3 seconds delay.
Fred
Michel
