Michel Jullian wrote:
>
> Fred I really meant "the reaction below", H2 combustion in O2:
>
> 2 H2 + O2 ----> 2 H2O
> 

 Gibbs Free Energy from CRC tables.
 
HOH     - 56.687 (liquid)
OH          + 8.18
HO-OH   - 28.78
H               +48.58
H2              0.00
O               + 55.39
O2              0.00


2 H2  (g) + O2 (g) ----->  2 H2O (liquid)

2 times -56.687 Kcal/mole or 2 x KJ/mole = - 475 KJ Gibbs Free Energy
for combustion of 2 moles of H2 at STP.

Measured innumerable times in a bomb calorimeter.
>
> How many joules per mole does this produce, and does this correspond to
the 
> enthalpy change or to the Gibbs free energy change of the reaction?
>
> The question is only intended to solve the controversy one way or
another, I 
> haven't looked up the answer. Admittedly I have my own opinion of what it 
> will be (enthalpy), so in this sense you can call it a trick question.
>
> Michel
>
> ----- Original Message ----- 
> From: "Frederick Sparber" <[EMAIL PROTECTED]>
> To: <[email protected]>
> Sent: Saturday, June 03, 2006 3:53 PM
> Subject: Re: Free Radical Chain Reactions
>
>
> > Michel Jullian wrote:
> >>
> >> BTW Fred, have you given some thought to our enthalpy vs Gibbs
> > controversy?
> >> Which energy can be recovered from the reaction below do you think, the
> >> enthalpy change or the Gibbs free energy change?
> >>
> > Is that a trick question, Michel?
> >
> > The H-H bond is 498 Kjoule/mole the same as the O-O bond and the O-H 
> > bond..
> > Hence overall,  H-H + O-O ---->  H-O-H   + O  nets Zip Gibbs or
Enthalpy.
> > But, O + Fe ---> Fe-O:  Fe-O (390 KJ/mole) minus  Fe-Fe (100 KJ/Mole)
> > equals a Gibbs Free Energy of 390-100 = 290 KJ when you oxidize iron
> > with O radicals.  :-)
> >
> > OTOH,  H-O-H  2 x 498 KJ/Mole + Ni ----> NiO  (382 KJ/mole) +
> > H-H = 498 - 382 =  116 KJ/mole. Easy to Compare Enthalpy
> > with the Ellingham (enthalpy) Diagrams.
> >
> > http://www.chem.mtu.edu/skkawatr/Ellingham.pdf
> >
> > Fred.
> >>
> >> Michel
> >>
> >> ----- Original Message ----- 
> >> From: "Frederick Sparber" <[EMAIL PROTECTED]>
> >> To: "vortex-l" <[email protected]>
> >> Sent: Friday, June 02, 2006 4:52 PM
> >> Subject: Re: Free Radical Chain Reactions
> >>
> >>
> >> > Actually  2 H2 + O2 ----> 2 H2O has about 14  reaction steps.
> >> >
> >> > http://www.cheresources.com/reactionkinetics3.shtml
> >> >
> >> > "Another important consideration is the formation of chain reactions.
> > The
> >> > basic premise of chain reaction mechanisms is also that free radicals
> > play
> >> > a leading role in the destruction of reactant molecules. The chain
> >> > reaction mechanism itself consists of several steps: initiation,
> >> > propagation, branching (not always present), and termination. This
can
> > be
> >> > illustrated, for certain range of temperature and pressure, by some
of
> > the
> >> > reactions in the following Hydrogen oxidation mechanism:"
> >> >
> >> > "To summarize, reaction mechanisms can be assembled from elementary
> >> > reactions using free radicals as the means for decomposition of the
> >> > reactant, and intermediate products. Chain branching reactions, if
they
> >> > occur, take a very important role in the mechanism as they lead to
the
> >> > formation of increasing concentrations of radicals. Reaction time and
> >> > temperature have a bearing on radical concentration, and the type of
> >> > reaction initiating the consumption of the reactant"
> >>
> >
> >
> > 
>



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