On Jan 8, 2008, at 3:01 PM, Michel Jullian wrote:
----- Original Message -----
From: "Horace Heffner" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Tuesday, January 08, 2008 11:50 PM
Subject: Re: [Vo]:Re: Cold Fusion-Treated Palladium-Lithium-Boron
Laser Fusion Target Factory
Let me try that one more time! As usual I made a slight error.
'
From the electric potential energy Pe for separating an electron and
proton we have:
'
Pe = k (-q)(q)(1/r) = -(2.88x10^-9 eV m) (1/r)
'
which we can rearrange to obtain r for a given potential energy,
'
r = (1.439965x10^-9 eV m) (1/Pe)
Mmm, all you did is multiply both sides by r/Pe it seems, how come
your constant got halved and changed sign from one line to the next?
Because I was cutting a pasting from a 2 deuteron intermediate fusion
state calculation which assumed:
Pe = k (-2q)(q)(1/r) = -(2.88x10^-9 eV m) (1/r)
because there are two deuterons in the state. I dropped the two, but
then started updating the rest with the second line upon recalculating.
The above should be
Pe = k (-q)(q)(1/r) = -(1.439965x10^-9) (1/r)
The formula:
r = (1.439965x10^-9 eV m) (1/Pe)
I think is correct, thus r = 1.846x10-15 m as posted. Radius is an
absolute value.
All just more errors due to my clerical incompetence!
Horace Heffner
http://www.mtaonline.net/~hheffner/
