It would depend on the initial state of the second battery. And you sure as hell can't quantify battery plate conditions enough to prove OU.
T On Thu, Mar 18, 2010 at 12:28 AM, Harry Veeder <[email protected]> wrote: > > > > > ----- Original Message ---- >> From: Terry Blanton <[email protected]> >> To: [email protected] >> Sent: Wed, March 17, 2010 7:40:21 PM >> Subject: Re: [Vo]:add on: OU demonstrated ( with no secrets) >> >> On Wed, Mar 17, 2010 at 1:19 PM, Harry Veeder < >> ymailto="mailto:[email protected]"; >> href="mailto:[email protected]";>[email protected]> wrote: > >> >> OK. I am just trying to understand what circumstances a voltage >> >> measurement by itself would be sufficient to prove OU. > > Never. >> Energy is measured by power expended over time. Electrical > power is >> voltage times current. Voltage transformations occur under > various >> conditions and can never indicate OU performance without > current or power and >> time measurements. > > > > If the input is provided by depleting a battery or a capacitor with a known > energy density and the output results in a fully charged battery or capacitor > with a greater energy density, then a voltage measurement should suffice. > > Harry > > > __________________________________________________________________ > Looking for the perfect gift? Give the gift of Flickr! > > http://www.flickr.com/gift/ > >
