Nothing mysterious about this circuit, it's a silly boost converter without a load. See:
http://en.wikipedia.org/wiki/Boost_converter 2010/3/18 Harry Veeder <[email protected]>: > > > > > ----- Original Message ---- >> From: Jed Rothwell <[email protected]> >> To: [email protected]; [email protected] >> Sent: Thu, March 18, 2010 5:22:20 PM >> Subject: Re: [Vo]:circuit diagram >> >> Stephen A. Lawrence wrote: > >>By the way, I should say "Thanks!" for >> taking the time to post all these >>here. It's interesting, even if I >> don't believe for a minute that it's OU. > > Someone should communicate the >> gist of the comments here to the > author of the video. Tell him to invest in >> an ammeter, for crying out loud. > > - Jed > > I am ignorant about electronics but I don't see what the fuss > is about since it is all DC current. If you know the resistance and the > voltage can't you safely infer that as the voltage rises and falls > so does the current? No, V=R*I works only on a pure resistor. An inductor or a capacitor obey different laws. > I still think that in certain "simple" circuits voltage measurements can > serve as a pretty good indicator of current and power. Not here. Michel
