2010/3/19 Harry Veeder <[email protected]>: > Here is a reply from Magluvin who is also a member of overunity.com: > "This is not a boost converter
I said it was a boost converter _without a load_. > as none of them will recharge the input > source(cap) while being operated. Ive tried. This is because he hasn't tried removing the load. If you do, in the course of one oscillation cycle, the input source first sources current, and then sinks current. Note there is a hidden component in the circuit which is important to understand where the inductor's current flows to and from in this no load operation, that's the MOSFET's output capacitance. The IRF640's antiparallel diode is another hidden component which plays an important role, it prevents the drain voltage from going below zero. Michel > And you wont find any > dc/dc converters with magnets on the coil core. ;]" > > Harry > > > > ----- Original Message ---- >> From: Harry Veeder <[email protected]> >> To: [email protected] >> Sent: Thu, March 18, 2010 10:46:19 PM >> Subject: Re: [Vo]:circuit diagram >> >> Ok, I gave him the wiki reference. > Harry > > > > ----- Original >> Message ---- >> From: Michel Jullian < >> ymailto="mailto:[email protected]"; >> href="mailto:[email protected]";>[email protected]> >> To: >> ymailto="mailto:[email protected]"; >> href="mailto:[email protected]";>[email protected] >> Sent: Thu, >> March 18, 2010 7:34:49 PM >> Subject: Re: [Vo]:circuit diagram >> >> >> Nothing mysterious about this circuit, it's a silly boost >> converter > without a >> load. See: > > >> target=_blank > >> href="http://en.wikipedia.org/wiki/Boost_converter"; target=_blank >> >http://en.wikipedia.org/wiki/Boost_converter > > 2010/3/18 >> >> Harry Veeder < >> href="mailto: >> href="mailto:[email protected]";>[email protected]"> >> ymailto="mailto:[email protected]"; >> href="mailto:[email protected]";>[email protected]>: >> >> >> >> >> >> >> ----- Original Message ---- >>> From: Jed Rothwell < >> >> ymailto="mailto: >> href="mailto:[email protected]";>[email protected]" >> >> href="mailto: >> href="mailto:[email protected]";>[email protected]"> >> ymailto="mailto:[email protected]"; >> href="mailto:[email protected]";>[email protected]> >>> >> >> To: >> href="mailto: >> href="mailto:[email protected]";>[email protected]"> >> ymailto="mailto:[email protected]"; >> href="mailto:[email protected]";>[email protected]; >> >> ymailto="mailto: >> href="mailto:[email protected]";>[email protected]" >> >> href="mailto: >> href="mailto:[email protected]";>[email protected]"> >> ymailto="mailto:[email protected]"; >> href="mailto:[email protected]";>[email protected] >>> Sent: Thu, >> >> March 18, 2010 5:22:20 PM >>> Subject: Re: [Vo]:circuit >> >> diagram >>> >>> Stephen A. Lawrence >> wrote: >> >>>By >> the way, I should say "Thanks!" >> for >>> taking the time to post all >> >> these >>>here. It's interesting, even if I >>> don't >> believe >> for a minute that it's OU. >> >> Someone should >> communicate >> the >>> gist of the comments here to the >> >> author of the video. >> Tell him to invest in >>> an ammeter, for >> crying out >> loud. >> >> - Jed >> >> I am ignorant >> about electronics but >> I don't see what the fuss >> is about since >> it is all DC current. If you >> know the resistance and the voltage can't >> you safely infer that as the voltage >> rises and falls >> so does >> the current? > > No, V=R*I works only on a >> pure resistor. An >> inductor or a capacitor > obey different laws. > >> I >> still >> think that in certain "simple" circuits voltage measurements can serve as >> >> a pretty good indicator of current and power. > > Not >> >> here. > > Michel > > > >> __________________________________________________________________ > Ask a >> question on any topic and get answers from real people. Go to Yahoo! Answers >> and >> share what you know at >> >http://ca.answers.yahoo.com > > > __________________________________________________________________ > Yahoo! Canada Toolbar: Search from anywhere on the web, and bookmark your > favourite sites. Download it now > http://ca.toolbar.yahoo.com. > >
