The toroid is also wired in differently from the inductor in the wiki diagram, but I suppose that doesn't matter either?
harry ----- Original Message ---- > From: Michel Jullian <[email protected]> > To: [email protected] > Sent: Fri, March 19, 2010 1:42:52 PM > Subject: Re: [Vo]:circuit diagram > > The capacitor on your photo 2 is in parallel with the battery so it's part of > the converter's input supply. The capacitor in the operating principles > diagram of the wikipedia article is the converter's output capacitor, which > might as well not be there in steady state is there is no load (once charged > it just stays charged at a high voltage, and the Boost's diode never > conducts-- so the diode might as well not be there either). So everything to > the right of the switch in the boost converter diagram could be removed in no > load condition, that's why I say the circuit operates like a Boost converter > without a load. Which explains why it steps up the input voltage, that's what > Boost converters do. Michel 2010/3/19 Harry Veeder < > ymailto="mailto:[email protected]"; > href="mailto:[email protected]";>[email protected]>: > I'll pass > that along. > But the capacitor looks like it is in the wrong place to be > a booster > converter with or without a load. > compare photo > 2: > > >http://tinyurl.com/ycw4xm4 > > with operating > principles > > target=_blank >http://en.wikipedia.org/wiki/Boost_converter > > > Harry > > > > > > ----- Original Message > ---- >> From: Michel Jullian < > ymailto="mailto:[email protected]"; > href="mailto:[email protected]";>[email protected]> >> To: > > href="mailto:[email protected]";>[email protected] >> Sent: Fri, > March 19, 2010 4:54:02 AM >> Subject: Re: [Vo]:circuit > diagram >> >> 2010/3/19 Harry Veeder < >> > href="mailto: > href="mailto:[email protected]";>[email protected]"> > ymailto="mailto:[email protected]"; > href="mailto:[email protected]";>[email protected]>: >> Here is > a >> reply from Magluvin who is also a member of > overunity.com: >> "This is not >> a boost > converter > > I said it was a boost converter _without a >> > load_. > >> as none of them will recharge the input >> > source(cap) >> while being operated. Ive tried. > > This is > because he hasn't tried removing >> the load. If you do, in the > > course of one oscillation cycle, the input source >> first > sources > current, and then sinks current. Note there is a > hidden >> component in > the circuit which is important to > understand where the >> inductor's > current flows to and from in > this no load operation, that's >> the > MOSFET's output > capacitance. The IRF640's antiparallel diode >> is > another > hidden component which plays an important role, it prevents > > the >> drain voltage from going below zero. > > > Michel > >> And you wont find >> any >> dc/dc > converters with magnets on the coil core. > ;]" >> >> >> > Harry >> >> >> > > > > __________________________________________________________________ > > Looking for the perfect gift? Give the gift of Flickr! > > > href="http://www.flickr.com/gift/"; target=_blank > >http://www.flickr.com/gift/ > > __________________________________________________________________ Looking for the perfect gift? Give the gift of Flickr! http://www.flickr.com/gift/
