In reply to Abd ul-Rahman Lomax's message of Sun, 04 Apr 2010 13:58:23 -0400: Hi, [snip] >>Takahashi has a serious problem here, because there is no decay mode >>which can release energy in numerous small energy packets - without >>an electron present in the nucleus - a possibility Takahashi has >>firmly denied in the past. If there were such a non-electron mode, >>e.g. coupling the energy across thousands of nuclei throughout the >>lattice, then the D + D -> He4 reaction could do the same, and there >>is no need for the Be8 model to begin with. Also, if you work out the >>geometry you will see that putting two D2 molecules into a >>tetrahedral site is not realistic. > >You mean into a single lattice site, I assume, but you are assuming >that the confinement site is within the clean lattice. The lattice >will contain defects that might be more accomodating. Further, >"putting two D2 molecules into a tetrahedral site" is definitely >difficult! First of all, putting one in is difficult; but the >question is "how difficult?" If there is one in a site already, and >conditions exerting pressure of D2 gas, how common would be a >transient occurrence of two? It could be very rare and very >transient, but it only takes a femtosecond or less to get some >fusion, according to Takahashi's calculations. I'd say that an urgent >task for the competent would be to verify this. Let me put it this >way, it's a different question than what Takahashi addressed: What >degree of confinement would be necessary before the TSC >formation/fusion would begin to have significant cross-section? [snip]
While Deuterium molecules may have difficulty fitting into a normal lattice, Deuterino molecules could do so easily. Furthermore, they could be magnetically bound with at least several eV of energy ensuring that they stay coupled together. The implication being that maybe a Mills catalytic process creates the molecules that then bind into the correct configuration due to magnetic forces, such that the Takahashi process can occur. If Takahashi shrinkage is rapid once the configuration is achieved, then this would also explain why his reaction happens before D-D fusion within the Deuterino molecule. The latter being relatively slow for "large" Deuterino molecules (which of course would nevertheless be several times smaller than normal Deuterium molecules). To make short story even longer, Deuterino molecules with e.g. p=4 (Mills favorite ;) would easily fit within a lattice, yet without Takahashi shrinkage they would take still take millions of years to fuse. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/Project.html
