You are misrepresenting the truth and misunderstanding. I made none of the
claims you presented and they are completely irrelevant to the subject. 3kW is
not negligible- one of Rossi's E-Cat's only supposedly vaporizes 2g/s of water
which takes less than 5kW. Obviously the steam is not dry. Also according to
Mattia Rizzi the true rate is 1/2 what Rossi states. Numbers aren't crucial to
seein the qualitative argument. Also the numbers you present aren't correct as
far as I know and I won't assume Rossi info is correct. Nevertheless thermal
inertia is real and will continue the boiling after power is shut off at the
same rate it was proceeding at before. Cooling of metal won't decline as fast
as "nuclear reaction rate" will unless the heater is a hoax to begin with. Why
would it take 15 minutes for the nuclear reaction to cease when 15 minutes is a
perfectly plausible time for continued steam production by thermal inertia. In
fact there's nothing about Rossi's steam E-Cat that is inconsistent with the
heat being supplied by electric heater only.
From: Jed Rothwell
To: [email protected]
Sent: Friday, August 26, 2011 5:45 PM
Subject: Re: [Vo]:The Krivit Videos Part 3
Joe Catania wrote:
There certainly are facts involved namely could the boiling be caused by
the heat stored in the metal, etc. of the E-Cat to last 15 minutes.
Facts. Hmmmm. . . . Okay then, tell us:
How much metal? How hot did it get? Assume 3 kWh are stored, enough to
vaporize 4.4 kg of water. Recall that 2 ordinary middle-aged professors easily
lifted the machine and put on a weight scale.
How long would it take to store up this heat with 3 kW maximum input? That is
the most you can input with ordinary wires. Remember your hypothesis is that
there is no anomalous heat, and therefore no input power after the electricity
is turned off. The only source of input energy is the ordinary wire shown going
into the machine, which cannot conduct more than 3 kW -- which is nowhere near
enough to even boil the water in the first place, but we'll ignore that. We
assuming that for some inexplicable reason their power meter is wrong, and
we'll ignore that, too. Remember also that they were boiling water before the
heat after death, and the temperature was already at the maximum. How did it
manage to store 3 kWh? You have 3 kW input, 12 kW goes to boiling, and some
other power goes to heating the metal to well over 1000°C. Perhaps you have in
mind they vectored the negative 10 kW into antimatter. Your model seems
implausible but as you say, there "certainly are facts" here.
How good would the insulation have to be so keep the metal from cooling off
during this storing-up period? How good do you think the insulation shown in
the photo might be? (Answer: not very.)
Where do you find a conventional joule heater or a wire going into the device
that can withstand such high temperatures? These are ordinary wires and a
machine made of ordinary steel, not nichrome.
Why didn't the 50 people attending the demonstration notice that the machine
was incandescent? Some of them held their hands over it. Some parts of the
machine metal are exposed.
I think you need to work on this model. I suggest you try doing some tests
with hot metal. You can heat a large chunk to incandescence and then drop it
into a pail of water, the way a blacksmith does. Measure the water temperature.
You will find it does not increase much. This demonstrate the tremendous
difference between the specific heat of water and metal. Just bringing the
water up to boiling temperature would take far more metal than this device has.
Vaporizing it would take hundreds of kilograms of metal, extremely well
insulated.
- Jed
