I don’t think that a screened proton (no charge) has less mass ( aka energy) as the unscreened proton.
Two screened protons or electrons will attract each other. On Sun, Aug 12, 2012 at 12:07 AM, David Roberson <[email protected]> wrote: > This is an informative discussion. I think that sometimes we group the > coulomb barrier energy with the energy associated with the strong force > once the proton in inside the nucleus. Once I tried to see if they were > separate and could find no reason that this would be true. I think that > both types of forces result in a change to the mass of the nucleus. > > Dave > -----Original Message----- > From: mixent <[email protected]> > To: vortex-l <[email protected]> > Sent: Sat, Aug 11, 2012 11:58 pm > Subject: Re: [Vo]:the Coil > > In reply to Axil Axil's message of Sat, 11 Aug 2012 23:37:00 -0400: > Hi, > [snip] > >*“This is clearly not true. If it were then hot fusion wouldn't work, and > >there* > >* * > > > >*would be no Sun. It takes less energy to get in than it takes to get out.* > >* * > > > >*The difference between the two is the net energy of the reaction.”* > > > >I said: “The coulomb barrier is symmetric. It takes as much energy to > >leave the nucleus as it takes to get in.” > > > >http://en.wikipedia.org/wiki/Alpha_decay > > Radioactive nuclei are in an excited state (i.e. above ground state) by > definition. That's the reason they are radioactive. > The ground state of e.g. 4He is way below that of 2 D's hence it's > energetically > favourable for 2 D's to combine and form 4He. > > In the radioactive case, it's easier to get out than to get in. In the case of > two D's it's easier to get in than to get out. So my statement about it being > easier to get in than to get out was too broad, as it only applies to fusion > reactions. It's the other way around for fission reactions. However in neither > case is the Coulomb barrier symmetric. > Regards, > > Robin van Spaandonk > http://rvanspaa.freehostia.com/project.html > >
