Do you agree that the conservation of mass-energy still holds under radioactive decay? If not, I need to do some learning.
Dave -----Original Message----- From: Axil Axil <[email protected]> To: vortex-l <[email protected]> Sent: Sat, Aug 11, 2012 11:49 pm Subject: Re: [Vo]:the Coil The barrier is not symmetrical because ofradioactive decay only. You get energy out during radioactive decay (i.e.,Alpha decay). This is due to QM tunneling. At its root, this energy increase comes from the uncertainty principle and is a matter ofpure chance. On Sat, Aug 11, 2012 at 11:44 PM, <[email protected]> wrote: In reply to David Roberson's message of Sat, 11 Aug 2012 23:30:47 -0400 (EDT): Hi, [snip] > >I think that it is symmetrical. If you begin outside of the nucleus and enter >energy is released. If you then reclaim that same amount of energy back to >the nucleus and allow the proton to exit, you will be at the same condition as >you started. The net round trip yields a balanced condition with no net >energy transferred. [snip] This is just a restatement of the conservation of energy. The very fact that you need to supply energy to the nucleus in order to prize a particle free proves that the barrier is not symmetrical. ...make that "prise a particle free" (That's what I had originally, but my spell checker didn't like it.) Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
