Yeah, the group can defeat the guy soundly!  I also believe that there is some 
form of coordinated effort that overcomes the coulomb barrier.  I am merely 
searching for the lost energy that is required and attempting to see from where 
it originates.  My suspicion is that the surrounding atoms become a bit cooler 
as the energy is borrowed from them.  Once the fusion occurs, all of the 
borrowed energy would of course be paid back.  The net effect is the same, but 
then there would be no free lunch.

Dave


-----Original Message-----
From: Axil Axil <[email protected]>
To: vortex-l <[email protected]>
Sent: Mon, Aug 20, 2012 12:48 pm
Subject: Re: [Vo]:Analysis of W-L theory as applicable to Rossi device -- Third 
paper


If you can think of the coulomb barrier as a soldier, a very good and strong 
one, this hero, can defeat any individual soldier of the opposing army. Even if 
the opposing army attacks our hero one fighter at a time the hero can resist 
the attack since the attack is uncoordinated. 
But when the opposing army gets its act together and acts a cohesive unit the 
hero is overcome by the combined and additive strength of the combined and 
coordinated action of the army.
The bigger that the coordinated army is, the more soundly that the hero is 
defeated.

Since electrons and protons are  waves also see:
 
http://en.wikipedia.org/wiki/Constructive_interference
 
 
Cheers:    Axil



On Mon, Aug 20, 2012 at 11:01 AM, David Roberson <[email protected]> wrote:

Axil, perhaps there is something going on that results in the lowering of the 
barrier.  I have to ask where the additional energy comes from to satisfy the 
actual energy needed?  If it is taken from other particles that might make 
sense, otherwise it sounds like a free lunch.
 
Dave



-----Original Message-----
From: Axil Axil <[email protected]>
To: vortex-l <[email protected]>
Sent: Mon, Aug 20, 2012 2:20 am
Subject: Re: [Vo]:Analysis of W-L theory as applicable to Rossi device -- Third 
paper


The super-atom produced as a large collection of coherent and entangled 
particles can completely lowers the Coulomb barrier. This is how atomic 
clustering fits into the LENR+ process. 
 
see
 
www.iscmns.org/work10/VysotskiiVapplicatio.ppt
 
 
Cheers:     Axil
 
 



On Mon, Aug 20, 2012 at 2:04 AM, Axil Axil <[email protected]> wrote:

According to this paper, clusters of atoms drop the coulomb barrier.The paper 
you reference  in thiis post sites this as acause of coulomb barrier lowering.
Cheers:   Axil
 
http://newenergytimes.com/v2/conferences/2012/ICCF17/ICCF-17-Vysotskii-Features-and-Giant-Acceleration.pdf




On Sun, Aug 19, 2012 at 6:51 PM, Jeff Berkowitz <[email protected]> wrote:

I read it too. The work has also been published in an influential peer-reviewed 
journal, JETP (Journal of Experimental and Theoretical Physics), a leading 
Russian journal also published in English:


http://www.springerlink.com/content/rup025083t105q83/ 


It is hard to know what to make of this. It says the Coulomb barrier drops away 
to low levels under conditions we can in principle control. If true, that would 
be ... big.


Wouldn't it be amusing if the "uncontrolled variable" that accounts for 
variation of results over the last 23 years turned out to be the RFI background 
in the vicinity of the experiment?


Jeff



On Sun, Aug 19, 2012 at 1:08 PM, Alan Fletcher <[email protected]> wrote:

> From: "Jeff Berkowitz" <[email protected]>
> Sent: Saturday, August 18, 2012 10:08:15 PM
> Subject: [Vo]:Analysis of W-L theory as applicable to Rossi device
> If you open this link:
> http://newenergytimes.com/v2/conferences/2012/ICCF17/ICCF-17-Vysotskii-Stimulated-LENR-Paper.pdf
>
>
> It turns out that the PDF contains three separate and unrelated LENR
> papers stuck together end to end.

The third paper is worth reading ... Harmonic oscillator explains the peaks in 
Hagelstein/Letts/Craven laser beat frequencies.

Ni+p => Cu+v reaction rate goes from 10^-1000 to 10^-4

Says it explains Rossi-Focardi ... except that they don't use a RF stimulator 
(any more?)











 




 

Reply via email to