This is a good find with possible relevance for Ni-H, Stewart, but many
observers will have a different take on how far one can take the BEC due to
thermal issues.

 

The classic "dipolar boson" and probably the only one which has a chance to
form a BEC at high temperature, since it has greatly reduced statistical
energy states which need to be aligned - is the short-lived nucleus
Helium-2. The following reversible nuclear reaction, common on the Sun,
lasts only a tiny fraction of a second:

 

P+P->2He->P+P

 

It is dipolar, since the only thing keeping it from happening permanently is
anti-aligned spin. The fact it forms at all, and so often, indicates how
easy it would be to fuse permanently, but for the spin. And yes, technically
it disproves Pauli, "if your clock is fast enough". Importantly, this is by
far the most common nuclear reaction in the Universe - 99.99+% of all
nuclear reactions on stars consist of only this reversible reaction.
Fortunately, on occasion, before the fused 2He can decay back to protons -
there will be a rare beta decay to deuterium, which is the ultimate source
of solar energy.. 

 

So while the basic reaction gives "almost no" net energy, since it starts
with protons and ends with protons. things could be very different in a warm
cavity environment, such as a nickel pore. In fact, although we often think
of a cryogenic BEC of consisting of tens of thousands of atoms - a warm BEC
involved in Ni-H at relatively high temperature could consist of only 4
atoms.

 

 

From: ChemE Stewart 

 

I ran across an interesting recent paper on the collapse of coherent dipolar
BECs when subject to confinement within an optical lattice.

 

http://arxiv.org/pdf/1205.5176v1.pdf 

 

Since Rydberg matter can act as a condensate if you remove the heat, I
thought this was applicable.  I realize the leap of faith in believing
something that happens @ approx.  300K-500K lower temperatures applies to
the CF case, but I see it just as believable as a fusion which typically
happens at multi-millions of degrees K higher temperatures.

David Roberson wrote:

It would be ideal if the pseudo neutron can be formed which would then
penetrate the nucleus but I am afraid that the energy equations would not
balance.  If there are two different paths to the same ultimate result, they
should release the same net energy.

 

 

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