On Jan 25, 2013, at 11:17 AM, David Roberson wrote:
Sometimes the emails do get crossed up with the number of
responses. In this particular case I think that my input helped to
clarify the problem to many others who may be following this
discussion.
I agree
My choice of observation locations proves that there are two bodies
or body equivalents that must exit the reaction. Now it is plain
for all to see that it is not possible for an alpha particle to be
the only result since I have demonstrated that the conservation of
momentum would be violated it this were to happen.
Before my mental example, it was just a statement that was difficult
to defend. Now we can more readily understand the type of reaction
that must take place in this form of fusion. For one, it is not
possible for an alpha with that total energy to be released. If we
could get a measure of the energy of the alphas that actually are
emitted, then that information can be directly used to calculate the
transferred momentum and energy which is received by the matrix.
Now, I have shown that some reactionary force is required through
which the energy and momentum is transferred to the system. This is
an important observation in my opinion.
Yes, Dave that is the basic conclusion that results from the law of
conservation of momentum. Thanks for making this clearer.
It is good that the members of vortex-l can discuss issues of this
nature since much is not known about the reactions that take place.
Sometimes a small spark of incite at the correct moment will lead to
added knowledge. Perhaps others now will realize that what I have
written here is educational. The next time, they might use my ideal
observation location or something of a similar nature to understand
other physics problems. Had I written a paper, it is likely that I
would have overlooked this particular tidbit of knowledge and left
out a major issue that should have been considered.
So, I suggest that we continue to engage in similar discussions
within vortex and enlarge our knowledge base since no one person is
required to be the holder of all that is important. Knowledge is
always advancing as more minds are engaged.
I vote for open discussion within vortex. And, my post was not a
waste of anybodies time.
Your point was not a waste. However, everyone should read every
message before replying.
Ed
Proof of this assertion will be from this point forth since most of
those engaged in the current discussion will now understand the
issue of energy and momentum requirements.
Dave
-----Original Message-----
From: Edmund Storms <[email protected]>
To: vortex-l <[email protected]>
Cc: Edmund Storms <[email protected]>
Sent: Fri, Jan 25, 2013 12:12 pm
Subject: Re: [Vo]:Chemonuclear Transitions
The problem with such exchanges is that the messages to different
people cross so that I have to explain the same thing several times,
which is a waste of time. That is why I write papers so that
everyone can study the same explanation.
On Jan 25, 2013, at 9:51 AM, David Roberson wrote:
Ed, I am confused by your statement that cold fusion is a 2-body to
1 body reaction. I see two reaction components unless I am missing
something. One is the alpha particle and the other appears in the
form of mass released as energy into the surrounding structure.
The energy release must result from emission of something. Normally
in hot fusion, the release results from emission of a strong gamma
when He4 forms. This gamma is not present when He4 forms during cold
fusion. Why not? The mechanism of energy transfer is obviously not
conventional, yet it must be consistent with the law of conservation
of momentum. I try to solve this problem in my theory. Most people
ignore the issue.
Ed
Every observer must see that the laws of physics apply to what he
sees. My favorite point is to be located precisely between the two
protons as they head toward each other with exactly the same
energy. In this location an observer sees that a finite amount of
kinetic energy is measured for the two particles and that there is
exactly zero momentum for the equal velocity pair. When they
collide together, there is no motion required for the resulting
alpha particle until it releases the excess energy. When that
energy is finally emitted in some form, then a reaction force would
result in relative motion of the alpha particle. In this manner,
both conservation of energy as well as conservation of momentum is
shown.
In my experience, when these laws are seen by any one observer,
then they are true for all of the others. Do you see a hole in
this argument? How are the laws true for others but not for the
one ideally located?
Dave
-----Original Message-----
From: Edmund Storms <[email protected]>
To: vortex-l <[email protected]>
Cc: Edmund Storms <[email protected]>
Sent: Fri, Jan 25, 2013 10:38 am
Subject: Re: [Vo]:Chemonuclear Transitions
The human mind is able to imagine endless possibilities. In order
to make any progress, a triage must be done by eliminating the
ideas that are so improbable or so illogical that they have very
little chance of being correct. That is what I'm attempting to do.
In any case, several basic rules MUST be considered. Hot fusion is
a conventional 2 body-2 body reaction as is required to carry away
the energy and momentum. Cold fusion is a 2-body to 1 body reaction
that violates this condition. That violation MUST be acknowledged
and explained.
People are not free to imaginary any thing. Certain rules are known
to apply. These rules are so basic that they MUST not be ignored.
Ed Storms
On Jan 25, 2013, at 8:22 AM, Daniel Rocha wrote:
d+d=n+He3 and d+d=t+p
What about d+d+...+d=? We don't know. This is what many many
particle models ends up being. Theyare hot fusion. The only
difference it is that there are many, more than 2>, incoming
nuclei to fuse. You cannot do that in experiments using colliders,
it is too unlikely. So, you cannot say that cold fusion is any
different than hot fusion that easily.
2013/1/25 Edmund Storms <[email protected]>
Yes, people try to explain LENR using the behavior described in
the paper.
--
Daniel Rocha - RJ
[email protected]
