In reply to David Roberson's message of Sun, 24 Mar 2013 23:26:56 -0400 (EDT): Hi, [snip] >For the above reasons there would be no energy loss as a result of the current >flow if it consisted of a continuous charge distribution orbiting a nucleus. >That is not true for a point charge following the same path.
For orbits below the ground state it is even true of point particles, because the change of angular momentum is less than h_bar. IOW it can't form a photon. (At least in my model ;) Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
