In many superconductors, the attractive interaction between electrons (necessary for pairing) is brought about indirectly by the interaction between the electrons and the vibrating crystal lattice (the phonons).
The same should be true for protons pairs. If Diprotons exist, the amazing conclusion is that charge screening can reach into the proton and completely cancel the charges on the quarks. This is what LENR is all about. What does that mean for QCD? On Sat, Apr 27, 2013 at 2:11 AM, <[email protected]> wrote: > In reply to Eric Walker's message of Fri, 26 Apr 2013 21:40:15 -0700: > Hi, > [snip] > > - In 3He, which is stable, electrostatic repulsion is felt between two > > nucleons, and the strong interaction is felt equally between all > nucleons. > > In deuterium, which is stable, there is no electrostatic repulsion, > and > > the strong interaction is felt equally between both nucleons. In a > > diproton, which is unstable, there is electrostatic repulsion, and > > presumably the strong interaction is in affect to the same extent as > > between the nucleons in a deuterium atom. Is the lack of stability of > the > > diproton due to a slight imbalance between electrostatic repulsion and > the > > residual strong force, or is it due to the combination of valence > quarks > > between the two nucleons not being quite right? > > IMO (and I emphasize opinion), there is no nuclear force between like > signed > nucleons. I.e. protons do not attract one another, nor do neutrons. There > is > only a force between protons and neutrons. That means that they have to > alternate in a nucleus. > This explains why there is no 2He, 3Li, 4Be etc. > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
