On Sat, Apr 27, 2013 at 2:11 AM, <[email protected]> wrote:
> In reply to Eric Walker's message of Fri, 26 Apr 2013 21:40:15 -0700: > Hi, > [snip] > > - In 3He, which is stable, electrostatic repulsion is felt between two > > nucleons, and the strong interaction is felt equally between all > nucleons. > > In deuterium, which is stable, there is no electrostatic repulsion, > and > > the strong interaction is felt equally between both nucleons. In a > > diproton, which is unstable, there is electrostatic repulsion, and > > presumably the strong interaction is in affect to the same extent as > > between the nucleons in a deuterium atom. Is the lack of stability of > the > > diproton due to a slight imbalance between electrostatic repulsion and > the > > residual strong force, or is it due to the combination of valence > quarks > > between the two nucleons not being quite right? > > IMO (and I emphasize opinion), there is no nuclear force between like > signed > nucleons. I.e. protons do not attract one another, nor do neutrons. There > is > only a force between protons and neutrons. That means that they have to > alternate in a nucleus. > This explains why there is no 2He, 3Li, 4Be etc. > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
