In reply to Edmund Storms's message of Fri, 24 May 2013 20:30:40 -0600: Hi, [snip] >First Eric, looking for deuterium would automatically see an increase >as well as a decrease. No additional effort is required. Second, what >reaction do you propose would use up the very small amount of D2 in H2?
f/H + D => 3He + fast electron (bremsstrahlung) or possibly f/H2(molecule) + D => 3He + fast proton (none) Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
