Jones, you are simply wrong. I have worked with tritium and I know how
it behaves. It cannot be detected using its Bremsstrahlund unless a
huge amount is present because this radiation is produced at only a
small fraction of the beta and is absorbed very quickly by only a
small amount of material in the case of tritium.
The video does not show anything about tritium. We simply do not know
or are told what is in the supposed light stick or how much tritium is
present. To the extent the container holding the tritium containing
fluid is thin enough to pass Bremsstrahlund and generate useful light,
the amount of tritium would be very dangerous if the container broke.
If Rossi had produce enough tritium to be detected this way, everyone
in the room would have serious health and legal problems if the
tritium got out of the E-Cat.
Ed Storms
On Jun 2, 2013, at 10:48 AM, Jones Beene wrote:
You do not need to remove the gas.
I know you have heard of Bremsstrahlung, even if the word is almost
unspellable to Anglos. Thank heavens for spell checkers and Wiki
vids. Here is a little video that tells you why Bianchini would see
tritium, if it was there.
https://www.youtube.com/watch?v=yYLzarnlcUE
It is not the beta decay which is seen – but instead it is the
secondary gammas aka Bremsstrahlung … and yes – they would be on the
edge of detectability, but a signal should show up above background
on his meter - especially when the Rossi device is disassembled, as
it is in the Penon report.
From: Jed Rothwell
Jones Beene wrote:
No. That is not correct. Tritium would have already have been
detected by
Bianchini if it was there . . .
I do not think so. Tritium would be trapped inside the cell. The
decay product is a low energy beta. If a little tritium leaks out of
the cell it is not likely to reach the detector, which only covers a
small amount of the surface surrounding the cell.
The only way Bianchini could detect this would be if Rossi makes a
cell with a high quality tube and connectors to the cell contents
and allows Bianchini to sample the gas. That is also the only way
anyone could detect an increase in deuterium or any other gaseous
nuclear product. This is a very difficult and involved thing to do.
You have to purge the tube and other hardware. You have to use
Swaglok connectors and you have to pay fanatical attention to
cleanliness. If you touch any part of metal where the gas will flow,
your fingerprint will contain more hydrogen than all of the reaction
products from several days of high temperature heat production.
Consider this: assuming the ratio of heat to helium is the same as
plasma fusion, a Pd-D automobile that runs for a year, producing as
much heat as the average gasoline burning automobile, will consume
roughly 1 g of D2O. That's 48 million miles per gallon of D2O.
- Jed
