what about the electrons in that stripping, and the neutrino...

does it stay positives?
what is the equation?

naively I imagine

np+np -> 4p + 2e +2!v

is it still positive?

electrons cost 511kev to create, about the gain...
I don't master enough to be sure of anything



2014-03-27 18:58 GMT+01:00 Jones Beene <[email protected]>:

>  Attention water-heads ("Mizuno" literally means 'From Water')
>
>
>
> Here is another weird and wonderful implication of the recent Mizuno paper
> which would explain how two deuterons react in such a way as to provide
> more energy than chemical but with few gamma rays and few neutrons - and
> with lots of hydrogen as the ash.
>
>
>
> Imagine that: hydrogen is the ash ! To explain this we must think outside
> the box, which is the same as inside the cavity.
>
>
>
> This could be called a QM "bi-stripping" reaction. It can only happen with
> two deuterons, and probably with the added requirement of nanocavity
> confinement. Heisenberg is involved.
>
>
>
> When a neutron decays to a proton, about 1.3 MeV would be released. But
> the extended half-life of free neutrons means this energy is not normally
> available instantaneously. This is where QM enters the picture.
>
>
>
> The mass of the deuteron is 1875.613 MeV. The mass of a free neutron plus
> a free proton is 1877.8374 - thus about 2.2 MeV would be required (to be
> supplied via kinetic energy) in order to split the deuteron - without QM
> being involved. The net deficit of this reaction is thus ~900 keV.
>
>
>
> This is why no one ever imagined Oppenheimer Philips as being relevant
> before now. It looks endothermic, without Heisenberg. However, one can
> surmise that with time alteration or compression - if two deuterons
> approach each other so that both undergo the OP splitting reaction
> instantaneously as a result of the single impact, then it is possible that
> the same 2.2 MeV of kinetic energy results in a net energy release of 2.6
> MeV (from two neutron decays) but the two neutrons have decayed to protons
> instantly, instead of with an extended half-life. This could indeed be an
> expected result of Heisenberg uncertainty and other QM principles.
>
>
>
> Thus the net reaction gain is 400 keV. The big stretch of the imagination
> is that the same kinetic energy can split both atoms at the same time using
> what can only be called a quantum time alteration and borrowed energy from
> the net reaction. Admittedly, this is a stretch, but isn't everything in QM?
>
>
>
> Adding QM into the mix, we can surmise that most of the 2.2 kinetic energy
> deficit is supplied from the net energy of the two neutron decay reactions,
> not a single decay - and also that the normal half life of neutrons is
> greatly compressed to supply this net energy of 2.6 MeV (2 x 1.3 MeV) as
> part of the borrowed input.
>
>
>
> Only then is the net reaction gainful and the beauty of it is that 4
> resultant protons carry off the 400 keV net gain - with approximately 100
> keV in kinetic energy each, which is at a level which is low enough and
> consistent with low or no gamma... and bremsstrahlung would not be high
> energy either. That there would appear to be few gamma rays (occasional) is
> a given. However, the ash of the reaction is that there would appear to be
> a lot of hydrogen which replaces the deuterium - which was there at the
> start.
>
>
>
> If you don't buy this explanation (that kinetic energy can be shared in
> such a way that two approaching deuterons are stripped at exactly the same
> time, and instantly decay) then there are alternatives. They will come up
> in a later post. In fact, to place this in context - there could be many
> gainful reactions happening at the same time.
>
>
>
> This bi-stripping hypothesis is all of a few minutes old, so it needs to
> be vetted... but hey, in QM terms - a few minutes is a virtual eternity J
>
>
>
> The free neutron mass is slightly larger than that of a proton. The
> lifetime is about 15 minutes. 939.565378 MeV compared to 938.272046 MeV
> would be the standard values.
>
>
>
> This is why the Oppenheimer Philips (stripping) reaction could be
> extremely important to LENR and it has been almost neglected in the past.
>
>
>
> It should be noted that in the parallel thread on vortex today (Magnetic
> permeability and LENR) that energy depletion of the deuteron, in the nickel
> cavity due to spin coupling, could lower the binding energy so that the OP
> effect happens at a much lower threshold than usual.
>
>
>

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