In reply to Eric Walker's message of Mon, 26 May 2014 08:37:09 -0700: Hi, [snip] >On Fri, May 23, 2014 at 7:52 PM, <mix...@bigpond.com> wrote: > >(However if you include the Ni mass in the energy density calculation and >> assume >> 1 H/Ni, then you get about 21640 eV / H atom which is beginning to stretch >> the >> friendship a bit.) >> > >Do your calculations make assumptions about the proportion of the fuel used >up by the E-Cat during the Elforsk test? Would this calculation be the >same if only 1 percent or 0.1 percent of the fuel were used up over the >course of the experiment?
No, it wouldn't. I calculated the minimum energy you have to get from each H atom, assuming they were all involved. If the energy released were to come from just a fraction of them, then obviously the energy release per atom involved would be higher. In practice I suspect that if f/H of any sort is involved, then there is probably an energy contribution from both shrinkage and some form of nuclear reaction. What percentage is contributed by each would probably vary (perhaps strongly). Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
