Eric--
One additional comment on the D excited state question.
Suppose in stead of one D you realize a pair of D's with their spin vectors
pointing in opposite directions in a coherent system like one may have in the
middle of a body centered cubic (BCC) cell of a Pd metal lattice or a Ni metal
lattice with a strong B magnetic field. Such a pair may act like a Cooper pair
with a 0 spin and hence a 4He nucleus. The transition from 2 D's to 4He could
occur via a distribution of mass energy to excited spin states of the lattice
electrons and/or metal nuclei. Proper alignment initially of the the D's may
be important to obtain antiparallel conditions and could be encouraged
statistically with varying magnetic fields and /or temperature of the lattice.
A quadruple oscillating electric field may also help to excite the D's to shed
their excess mass relative to the developing 4He particle.
The magnetic field should actually reduce the spatial options available in the
BCC cell for the D's that happen to be there and improve the statistics for
their arriving at the same location to form a Cooper pair. The spin coupling
may be a strong tendency in such a situation. It is with electrons as Pauli
pointed out.
Bob
----- Original Message -----
From: Eric Walker
To: vortex-l@eskimo.com
Sent: Friday, October 17, 2014 9:54 PM
Subject: Re: [Vo]:Mizuno, Rossi & copper transmutation
On Fri, Oct 17, 2014 at 10:41 AM, Bob Cook <frobertc...@hotmail.com> wrote:
Do you know if the experiments looked at excited spin energy states that
may be possible at higher spin quanta?
Unfortunately I don't have any other details and don't know of a particular
experiment to refer to. Here is the quote from a textbook I recently finished
reading:
For nuclear physicists, the deuteron should be what the hydrogen atom is
for atomic physicists. Just as the measured Balmer series of electromagnetic
transitions between the excited states of hydrogen led to an understanding of
the structure of hydrogen, so should the electromagnetic transitions between
the excited states of the deuteron lead to an understanding of its structure.
Unfortunately, there are no excited states of the deuteron—it is such a weakly
bound system that the only "excited states" are unbound systems consisting of a
free proton and neutron. [1]
Eric
[1] Kenneth S. Krane, Introductory Nuclear Physics, pp. 80-81; author's
emphasis.
