Axil--
Take a look at the Norman Cook discussion that you just posted as to the
depletion of the various isotopes of Ni in LENR testing that Cook evaluates.
IT INCLUDES DEPLETION OF ODD NUCLEON ISOTOPES WITH NET SPIN (NI-59 WITH -3/2)
AS WELL AS EVEN NUCLEON ISOTOPES WITH 0 SPIN. ONLY NI-61 (ODD NUMBER OF
NUCLEONS) DOES NOT SEEM TO REACT MUCH.
Bob Cook
----- Original Message -----
From: Axil Axil
To: vortex-l
Sent: Saturday, October 18, 2014 4:11 PM
Subject: Re: [Vo]:Mizuno, Rossi & copper transmutation
There is good reason to believe that magnetism is the prime mover in LENR.
Under this speculative paradigm, it is interesting to consider the options and
consequences of this conjecture. In such a paradigm, any technology that is
friendly to magnetism would be good for LENR, and conversely, a technology that
undercuts the strength of magnetism is bad.
The Pd/D wet technology is more unfriendly to magnetism than nickel because
it makes magnetism more difficult to maintain. Firstly as a general
technological principle, an isotope must have a nuclear spin of zero to enable
the LENR reaction. There is much experimental evidence to support this
conjecture. For an explanation see below. In this respect, palladium has a
nuclear spin profile that is about 78% effective. 105Pd has a non-zero spin and
is 22% of the isotopic contents of run of the mill palladium.
On the other hand, Nickel is much more efficient in terms of supporting
magnetism. 61Ni has a non-zero nuclear spin, but that isotope is only 1.14% of
the isotopic content of Nickel.
Palladium is paramagnetic and Nickel is ferromagnetic. So nickel is more
desirable than palladium as a magnetic reaction catalyst.
In more detail, this thinking is underpinned by a speculative LENR reaction
rule that is interesting to explore. That rule is that the LENR reaction must
occur among atomic ions that have zero nuclear spin.
In explanation, Nuclear magnetic resonance (NMR) is a physical phenomenon in
which nuclei in a magnetic field absorb and re-emit electromagnetic radiation.
This energy is at a specific resonance frequency which depends on the strength
of the magnetic field and the magnetic properties of the isotope of the atoms;
in practical applications, the frequency is similar to old style VHF and UHF
television broadcasts (60–1000 MHz). NMR allows the observation of specific
quantum mechanical magnetic properties of the atomic nucleus.
All isotopes that contain an odd number of protons and/or of neutrons have an
intrinsic magnetic moment and angular momentum, in other words a nonzero spin,
while all nuclides with even numbers of both have a total spin of zero. The
most commonly studied NMR active nuclei are 1H and 13C, although nuclei from
isotopes of many other elements (e.g. 2H, 6Li, 10B, 11B, 14N, 15N, 17O, 19F,
23Na, 29Si, 31P, 35Cl, 113Cd, 129Xe, 195Pt) have been studied by high-field NMR
spectroscopy as well.
It is now known that Ni61 does not participate in the LENR reaction. Ni61 is
a NMR active isotope. When a magnetic field is applied to an NMR active
isotope, the magnetic energy imparted to the nucleus is dissipated by induced
nuclear vibrational energy which is radiated away as rf energy. The non-zero
spin of the the nucleus shields the nucleus from the external magnetic field
not allowing that field to penetrate into it. External magnetic fields catalyze
changes in the protons and neutrons in the nucleus as well as enabling
accelerated quantum mechanical tunneling. If this external magnetic field is
shielded by NMR activity, LENR transmutation of the protons and neutrons in the
nucleus is made more difficult.
Therefore, during the course of an extended LENR reaction cycle, isotope
depletion will tend to favor the enrichment and buildup of NMR active elements.
Hydrogen with non-zero spin will not participate in the LENR reaction whereas
cooper pairs of protons will. Expect LENR reactions centered on pairs of
protons with zero spin.
Also, as the LERN reaction matures and more NMR active isotopes accumulate,
the LENR reactor will put out increasing levels or rf radiation derived from
the nuclear vibrations of the NMR isotope.
This NMR thinking also applies to the nature of the various isotopes of
hydrogen.
Molecular hydrogen occurs in two isomeric forms, one with its two proton
spins aligned parallel (orthohydrogen), the other with its two proton spins
aligned antiparallel (parahydrogen). At room temperature and thermal
equilibrium, hydrogen consists of approximately 75% orthohydrogen and 25%
parahydrogen.
Orthohydrogen hydrogen has non zero spin, this is bad for Ni/H LENR because
the non zero spin wastes magnetic energy by producing RF radiation.
Parahydrogen hydrogen has zero spin. This is good for Ni/H LENR because this
type of hydrogen is magnetically inactive.
This is a way to increase parahydrogen hydrogen by using a noble metal
catalyst.
see
Catalytic process for ortho-para hydrogen conversion
http://www.google.com/patents/US3383176
Could this metallic ruthenium and certain ruthenium alloys be Rossi's secret
sauce?
The first step in the hydrogen doublet fusion process is the formation of one
or more atoms of 2He.
Helium-2 or 2He, also known as a diproton, is an extremely unstable isotope
of helium that consists of two protons without any neutrons. According to
theoretical calculations it would have been much more stable (although still
beta decaying to deuterium) had the strong force been 2% greater. Its
instability is due to spin-spin interactions in the nuclear force, and the
Pauli exclusion principle, which forces the two protons to have anti-aligned
spins and gives the diproton a negative binding energy.
By the way, the ash produced by the LENR reaction will have a non-zero
nuclear spin such as lithium, boron, and beryllium. This is due to the fact
that the ash is at the end of the LENR reaction chain that terminates with an
isotope featuring a non-zero nuclear spin.
Furthermore, all the stable isotopes of copper have a non-zero nuclear spin.
This may be way these isotopes are found in the ash assay of Rossi’s reactor.
One last correlation remains.
It seems that the popular wet LENR catalyst acts like a superconductor for
protons where protons pair up into a cooper pair.
See
http://arxiv.org/pdf/0807.1386.pdf
This work emphasizes that atoms in the crystal-field of KHCO3 are not
individual particles possessing properties in their own right. They merge into
macroscopic states and exhibit all features of quantum mechanics: non-locality,
entanglement, spin-symmetry, superposition and interferences. There is every
reason to suppose that similar quantum effects should occur in many hydrogen
bonded crystals undergoing structural phase transitions.
I understand spin-symmetry to mean a zero spin.
This catalyst provides a proton dimer of zero spin to the wet LENR reaction.
This is the reason why this catalyst enhances electrolytic LENR in water.
On Sat, Oct 18, 2014 at 6:38 PM, Bob Cook <[email protected]> wrote:
I would disagree with the spins reported by Axil for D and a Proton. D is
+1 and the Proton is +1/2 in non excited states or ground states. The neutron
also has a +1/2 spin. The proton and neutron spins seem to add to make up the
+1 spin of the D.
Bob
----- Original Message -----
From: Jones Beene
To: [email protected]
Sent: Saturday, October 18, 2014 12:17 PM
Subject: RE: [Vo]:Mizuno, Rossi & copper transmutation
From: Axil
it is highly preferable to use deuterium, as opposed to hydrogen.
I disagree.
Deuterium has a non zero spin whereas hydrogen has a zero spin which is
required in low powered LENR reactions.
Says who? What is your evidence?
