How do SPPs convey the heat away from the NAE so that the nanoscale is NOT the hottest spot? SPPs normally attenuate at very small scale, and the attenuation is electromagnetic absorption of the lossy plasmon waveguide. If the NAE is the hottest spot in the reactor, then there could never be a meltdown because the NAE would evaporate before the macro-scale apparatus got hot enough to melt. It is only if the heat is conveyed away from the NAE that in a short term high output burst that the NAE could heat its environment hotter than itself and cause a meltdown. In steady state, the NAE eventually heats back to the temperature of the environment by radiant IR heating and convection.
On Sat, Oct 18, 2014 at 6:08 PM, Jones Beene <[email protected]> wrote: > Another remote possibility should be mentioned, if real gain is found in > this device… and that would be this: the basis of gain could be only SPP – > surface plasmon polaritons. This species may be gainful in itself as it > condenses. Electrons would be lost to the Dirac sea via SPP, for instance - > but with a relic such as spin retained in 3-space. > > > > Again that may seem remote to you now, but to someone who has studied SPP > it is more probable than magic gamma ray absorbers, the infamous gram of > magic fuel for 30 days, magic internal cooling to protect the fuel, magic > fuel rejuvenation of surface features, and the dozen or so other miracles > necessary for this device to be related to nuclear fusion. > > > > What are the main objections to a SPP modality? > > > > Jones > > > > *From:* Bob Higgins > > > > … Think about it like a microwave oven (only x-rays instead of > microwaves). The oven walls don't initially get hot. The food inside gets > hot from the microwave absorbtion and the IR from the food then heats up > the walls of the oven. > > >
